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ICE Princess25 [194]
4 years ago
15

Suppose a person whose mass is m is being held up against the wall with a constant tangential velocity v greater than the minimu

m necessary. find the magnitude of the frictional force between the person and the wall.
Physics
2 answers:
Naddika [18.5K]4 years ago
7 0
In the magnitud is in good
Kamila [148]4 years ago
7 0

Answer:

friction force must be equal to the magnitude of weight of the object

Explanation:

When the object is stuck against the wall

then we will have

F_n = \frac{mv^2}{r}

also we know that

mg = F_f

so if the block is at rest and not sliding then in vertical direction the force must be balanced

so here we can say

F_g = F_f

so friction force must be equal to the magnitude of weight of the object

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The compass of an airplane indicates that it is headed due north and its airspeed indicator shows that it is moving through the
yarga [219]

Answer:

Airplane speed relative to the ground is 260 km/h and θ = 22.6º  direction from north to east

Explanation:

This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.

Let's take the north direction with the Y axis and the east direction as the X axis

         Vy = 240 km / h            airplane

         Vx = 100 Km / h              wind

a) See the annex

Analytical calculation of the magnitude of the speed and direction of the aircraft

         V² = Vx² + Vy²

         V = √ (240² + 100²)

         V = 260 km/h

Airplane speed relative to the ground is 260 km/h

         Tan θ = Vy / Vx

         tan θ = 100/240

         θ = 22.6º

           

Direction from north to eastb

b) What direction should the pilot have so that the resulting northbound

          Vo = 240 km/h      airplane

          Vox = Vo cos θ

          Voy = Vo sin  θ

          Vx = 100 km / h      wind

To travel north the speeds the x axis (East) must add zero

         Vx -Vox = 0

         Vx = Vox = Vo cos θ

         100 = 240 cos θ

          θ = cos⁻¹ (100/240)

          θ = 65.7º

North to West Direction

The speed in that case would be

           V² = Vx² + Vy²

To go north we must find Vy

          Vy² = V² - Vx²

          Vy = √( 240² - 100²)

          Vy = 218.2 km / h

8 0
4 years ago
How long does it take to reach the moon?
alexdok [17]

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

  • It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles

  • In the year 1969 the first man (Neil Armstrong ) landed on the moon, the journey took him 8 days, 3 hours, 18 minutes, 35 seconds, on 16 July.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

Learn more about Space and moon exploration:

brainly.com/question/3983943

5 0
3 years ago
Read 2 more answers
A Hammer is an example of a _____________ Machine
Nesterboy [21]
A hammer is a type of lever.
6 0
4 years ago
Read 2 more answers
Determine the average acceleration for x(t)=19t^2+7t^3 for a time interval between 3 and 9 seconds
AleksandrR [38]

Answer:

290

Explanation:

Average acceleration is the change in velocity over change in time.

First, find the velocity by taking the derivative of position.

v(t) = dx/dt

v(t) = 38t + 21t²

At t = 3 and t = 9:

v(3) = 303

v(9) = 2043

So the average acceleration is:

a = Δv / Δt

a = (2043 − 303) / (9 − 3)

a = 290

Use appropriate units.

7 0
3 years ago
The mass of the earth is 5.98 1024 kg, the mass of the moon is 7.36 1022 kg, and the distance between the centers of the earth a
Setler [38]

Answer:

 x_{cm} = 4.644 10⁶ m

Explanation:

The center of mass is given by the equation

         x_{cm} = 1 / M_{total}  ∑ x_{i}  m_{i}

Where M_{total} is the total masses of the system, x_{i} is the distance between the particles and m_{i} is the masses of each body

Let's apply this equation to our problem

        M = Me + m

        M = 5.98 10²⁴ + 7.36 10²²

        M = 605.36 10²² kg

Let's locate a reference system located in the center of the Earth

Let's calculate

       x_{cm} = 1 / 605.36 10²²   [Me 0 + 7.36 10²² 3.82 10⁸]

       x_{cm} = 4.644 10⁶ m

4 0
3 years ago
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