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Ilya [14]
4 years ago
14

n object moves with a constant speed of 30 m/s on a circular track of radius 150 m. What is the acceleration of the object

Physics
1 answer:
posledela4 years ago
5 0
Acceleration is zero because it is travelling at a constant speed.
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Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
Marysya12 [62]
From the law of conservation of momentum
m1u1+ m2u2= m1v1+ m2v2
110*8+ 110*-10= 110*-10 + 110* v2
v2= 8 m/sec
8 0
3 years ago
Use a common denominator to find-2/3 + -4/5​
Juliette [100K]

Answer:

-22/15

Explanation:

the least common denominator is  15 so first you multiply -2/3 by 5 in both the numerator and denominator making it -10/15

Then you do the same to -4/5 except you multiply the numerator and denominator by 3 giving you -12/15

If you add -10/15+ -12/15 you get -22/15

6 0
3 years ago
Which force is always directed toward the center of a circle?
vova2212 [387]
The answer is D. centripetal force
This definition of centripetal force is a force acting towards the center of an object moving in a circular motion. Acceleration is the rate of which velocity changes over a period of time. If you pick a point on say a rotating circle and find the tangential velocity at each point it goes through, the acceleration would be towards the middle. 
6 0
3 years ago
A car travels 70 km in two hours 104 km in the next 1.5 hours and then 79 km in two hours before reaching its destination what w
stiks02 [169]

Average speed = (total distance) / (total time)

Total distance = (70km + 104km + 79km) = 253 km

Total time = (2hr + 1.5hr + 2hr) = 5.5 hrs

Average speed = (253 km) / (5.5 hrs)

<em>Average speed = 46 km/hr</em>

4 0
3 years ago
An electron with speed of 104 m/s enters a ""forbidden"" region where an electric force tries to push it back along its path wit
dangina [55]

Answer:

The distance travelled is 151.22m and it took 0.97s

Explanation:

Well, this is an ARM problem, so we will need the following formulas

x(t)=x_{0} +v_{0} *(t-t_{0} )+0.5*a*(t-t_{0} )^{2}

v(t)=v_{0} +a*(t-t_{0} )

where x_{0} is the initial position (we can assume is zero), v_{0} is the initial speed of 104 m/s, t_{0} is the initial time (we also assume is zero), a is the acceleration of 107 m/s2, v is speed, x is position and t is time.

Now that we have the formulas, we know that when the electron stops it has no speed. Then we calculate how much time it takes to stop.

0=104m/s-107m/s^{2} *t\\t=0.97s

Finally, we calculate the distance travelled in this time

x(0.97s)=104m/s*0.97s+0.5*107m/s^{2}*(0.97s)^{2}=151.22m

5 0
3 years ago
Read 2 more answers
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