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Ira Lisetskai [31]
1 year ago
7

Pls tell me how to solve this!

Chemistry
1 answer:
Anna35 [415]1 year ago
8 0

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

⠀

\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}

⠀

⠀

⠀

<u>Let</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>from</u><u> </u><u>pinhole</u><u> </u><u>=</u><u> </u><u>t</u><u> </u><u>seconds</u>

⠀

⠀

\textsf {Rate of hydrogen } \sf(H_2) =  \frac{50}{t}

⠀

⠀

⠀

According to the formula

\sf \frac{Rate  \: of  \: hydrogen(H_2)}{Rate \:  of \:  oxygen(O_2) }  =   \sqrt{ \frac{Molar \: mass \: of \:  O_2}{Molar  \: mass \: of \: H_2} }

⠀

⠀

\large  \sf  \frac{50}{t}  \div  \frac{50}{60}  =  \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} }  \\  \\  \sf   \large \frac{ \cancel{50}}{t}  \times  \frac{60}{ \cancel{50}}  =  \sqrt{16}  \\  \\  \sf   \large \frac{60}{t}  = 4 \\  \\  \sf \large  \frac{ \cancel{60} \:  \small12}{ \cancel4}  = t \\  \\    \large \underline{ \boxed{ \tt t = 12 \: seconds}}

⠀

⠀

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<h3><u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u> </u><u>seconds</u><u>.</u><u> </u></h3>

⠀

⠀

<h2>Thank you!</h2>
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