The nucleus of an atom of any element is located at the very center. It contains subatomic particles, proton and neutron. That's why it contains the greater mass, because only the electrons orbit the nucleus. So, you would expect the arrow to point somewhere in the center. A picture of nitrogen's nucleus is shown in the attached picture.
Answer:
KNO3- Potassium Nitrate, KOH- Potassium hydroxide, K2CRO4- Potassium chromate
Explanation:
Answer:
92.01 g/mol
Explanation:
So first you need to find the empirical formula by the percents. That would be, assuming that you have 100 grams of the the sample, divide each quantity of each element found by its respective molar mass.
30.4 g of N ÷ 14 g/mol N= 2.17 mol of N
69.6 g of O ÷ 16g/mol= 4.35 mol of O
You can establish now the empirical formula.
N2.17O4.35,
but since you can't have a decimal subscript, you divide each subscript by the minimum subscript
NO2
So then you're said that the molecular formula derived from that empirical formula has 2 nitrogen, so you multiply all the subscripts, by 2:
N2O4
-Dinitrogen Tetraoxide
-Nitrogen oxide (IV)
Then all you have to do is find the molecular mass of the compound using the periodic table and what you obtain is the molar mass.
remember: molecular mass is correspondent to molar mass.
Answer:
(a)
(b)
(c)
Explanation:
(a)
The given compound is silicon tetrabromide. It means that 1 silicon and four bromine atoms are combined to form the molecule.
The chemical formula of silicon tetrabromide is
(b)
The given compound is disulfur dichloride. It means that 2 sulfur atoms and 2 chlorine atoms are combined to form the molecule.
The chemical formula of disulfur dichloride is
(c)
The given compound is diphosphorus hexaoxide. It means that 2 phosphorus atoms and 6 oxygen atoms are combined to form the molecule.
The chemical formula of diphosphorus hexaoxide is
N2 + 3H2 --> 2NH3
When 100g of N2 , no of moles of N2= 100/(28)=3.57 mol
no. of moles of h2 = 6/(2)=3mol
Therefore h2 is limiting reagent.
no. of moles of ammonia= 3/3*2=2moles
mass of ammonia produced= 2 mol * (14+3)= 34g
