The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.
The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.
Explanation:
The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.
So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).
Then, the heat energy required to raise the temperature will be
Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.
Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100 °C.
Then, the heat energy required to raise its temperature will be
And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.
So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.
Answer:
Explanation:
The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
Data:
p₁ =5.7 atm; T₁ = 100.0 °C
p₂ = ?; T₂ = 20.0 °C
Calculations:
1. Convert the temperatures to kelvins
T₁ = (100.0 + 273.15) K = 373.15
T₂ = (20.0 + 273.15) K = 293.15
2. Calculate the new pressure
Answer: There are molecules
gas are in 756.2 L.
Explanation:
It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of moles present in 756.2 L are calculated as follows.
According to mole concept, 1 mole of every substance contains molecules.
Therefore, molecules of S present in 33.76 moles are calculated as follows.
Thus, we can conclude that there are molecules
gas are in 756.2 L.