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mr_godi [17]
3 years ago
13

A is more linear than wich

Chemistry
1 answer:
bekas [8.4K]3 years ago
4 0
You should put a picture or finish the question
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Exactly how much time must elapse before 16 grams of potassium-42decays, leaving 2 grams of the original isotope?(1) 8 × 12.4 ho
AleksandrR [38]
The answer is <span>(3) 3 × 12.4 hours
</span>
To calculate this, we will use two equations:
(1/2) ^{n} =x
t_{1/2} = \frac{t}{n}
where:
<span>n - number of half-lives
</span>x - remained amount of the sample, in decimals
<span>t_{1/2} - half-life length
</span>t - total time elapsed.

First, we have to calculate x and n. x is <span>remained amount of the sample, so if at the beginning were 16 grams of potassium-42, and now it remained 2 grams, then x is:
2 grams : x % = 16 grams : 100 %
x = 2 grams </span>× 100 percent ÷ 16 grams
x = 12.5% = 0.125

Thus:
<span>(1/2) ^{n} =x
</span>(0.5) ^{n} =0.125
n*log(0.5)=log(0.125)
n= \frac{log(0.5)}{log(0.125)}
n=3

It is known that the half-life of potassium-42 is 12.36 ≈ 12.4 hours.
Thus:
<span>t_{1/2} = 12.4
</span><span>t_{1/2} *n = t
</span>t= 12.4*3

Therefore, it must elapse 3 × 12.4 hours <span>before 16 grams of potassium-42 decays, leaving 2 grams of the original isotope</span>
7 0
3 years ago
Read 2 more answers
Calculate the kinetic energy of a baseball (mass = 5.25 oz) with a velocity of 1.0 x 10^2 mi/h
pychu [463]

Answer:

262.5 Joules

Explanation:

You find the kinetic energy of multiplying half of the mass by the velocity. In this word problem it tells you the mass so you divide it by 2. That answer is 2.625, you then multiply that by the velocity, in this instance it's 1.0 x 10^2 mi/h.

The unit in kinetic energy is Joules. This is actually a really important part in chemistry and physics.

5 0
2 years ago
5. A gas occupies a volume of 100.0 mL at 27.0°C and 630.0 torr. At what temperature, in degrees
DanielleElmas [232]

100 by 500 ml so if you put 50 ml in 630torr it would evaporate

Explanation:

it is more than ¹00 celcwius so it would eveporate

8 0
3 years ago
Nitrogen gas is introduced into a large deflated plastic bag. No gas is allowed to escape, but as more and more nitrogen is adde
Natalija [7]

Answer:

0.9307 moles have been introduced into the bag.

Explanation:

Pressure of the gas within the bag,P = 1.00 atm

Temperature of the gas remains at room temperature,T=20.0 °C = 293.15 K

Volume of the gas in the bag = V = 22.4 L

Number of moles of gas = n

Using an ideal gas equation:

PV=nRT

1.00 atm\times 22.4 atm=n\times 0.0821 atm l/mol K\times 293.15 K

n = 0.9307 moles

0.9307 moles have been introduced into the bag.

4 0
3 years ago
How many particles are there in 2.8 moles of CO2
Drupady [299]

Answer:

Moles = Molecules / (6.0221415 x 10^23)

Explanation:

3 0
3 years ago
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