All categories

3 years ago

Just need help with this last question

Chemistry

2 answers:

uranmaximum [27]3 years ago

6 0

Answer:

Explanation:

Potential energy is obtained by an object's positioning so the first and last choice cannot be correct.

Of course the electrical energy is not destroyed so that one's not correct either.

The energy conversion that takes place must be electrical energy to light and heat.

ella [17]3 years ago

5 0

its electrical energy -------> light and heat

Hope this helps

mark brainliest if helpful

You might be interested in

About 55L of a gas in a flexible container is under a pressure of 3.2 atm and at a temperature of 520K. What is the new volume o

vampirchik [111]

Answer:

30.62 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 55 L

Initial pressure (P₁) = 3.2 atm

Initial temperature (T₁) = 520 K

Final temperature (T₂) = 760 K

Final pressure (P₂) = 8.4 atm

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

3.2 × 55 / 520 = 8.4 × V₂ / 760

176 / 520 = 8.4 × V₂ / 760

Cross multiply

520 × 8.4 × V₂ = 176 × 760

4368 × V₂ = 133760

Divide both side by 4368

V₂ = 133760 / 4368

V₂ = 30.62 L

Therefore, the new volume of the gas is 30.62 L

7 0

3 years ago

Concert 15 cm3 to liters

musickatia [10]

The answer to your problem is 0.015 liters. I got the answer because to convert cubic centimeters into liters, you need to divide the cubic centimeters by 1000.

8 0

2 years ago

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

4 0

3 years ago

How do you make chocolate milk

Dennis_Churaev [7]

Mix milk with chocolate syrup or powder.

8 0

3 years ago

Read 2 more answers

What is the current in the 30 ohm heating coil of a coffee maker that operates on a 120 volt circuit?

SpyIntel [72]

Answer:

4Amps. i can't see other questions clearly

Explanation:

$using ohms law \\ v = ir$

V=120 volt
R=30ohms
I=?

I=V/R

I=120/30

I=4amps

8 0

3 years ago