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never [62]
2 years ago
8

The given diagram shows the steps for constructing a line parallel to line AB and passing through point P, but an error has occu

rred in the construction. What needs to be corrected in the diagram to fix the error? A. The third arc should be drawn centered at point F. B. A fourth arc needs drawn so that it passes through point P. C. The second arc should be drawn centered at point D. D. The first arc should pass through point B.
Mathematics
1 answer:
Fed [463]2 years ago
6 0

<u>Construction</u> is a process in which required<em> steps</em> are considered to draw a given shape by the use of construction <u>instruments</u> and <u>materials</u>. Thus to correct the <u>error</u> in the given question, the third arc should be drawn <u>centered</u> at point F. Answer is option A.

Majorly, the use of a<em> straight edge</em> and a <u>pair</u> of compasses to draw the image of a given object is referred to as <u>construction</u>. Which required <em>adhering </em>to some steps.

The <em>construction</em> of a <u>parallel</u> line through a <em>given</em> point to a given <em>line </em>involves following the <u>appropriate</u> procedure. If not, an error would be committed which would result in an i<em>nappropriate</em> shape or figure.

Therefore, to fix the <u>error</u> in the given question, it is important that the <em>third</em> arc should be drawn<u> centered</u> at point F. Thus, the correct answer is <em>option</em> A.

For more clarifications on the construction of a parallel line through a given point to a given line, visit: brainly.com/question/2180353

#SPJ1

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Step-by-step explanation:

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What is the slope of the line with equation 10x + 15y = -90?
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Answer:

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Step-by-step explanation:

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USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
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Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

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Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

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We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

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Now,

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f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

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Step-by-step explanation:

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