Help me!! i am not good at this virtual algebra stuff
1 answer:
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Answer:
See below.
Step-by-step explanation:
See the attached chart that shows all outcomes for two dice.
There are 36 possible outcomes, all equally likely (if the dice are fair!).
The probability of getting a sum of 2 is 1/36 (only one way to get 2: both dice show 1).
The probability of getting a sum of 3 is 2/36 = 1/18.
The probability of getting a sum of 7 is 6/36 = 1/6 (the most likely sum!)
(Notice how all the sum = 7 outcomes like on a diagonal in the chart?)
The probability of getting a sum of 11 is 2/36 = 1/18.
The probability of getting a sum of 12 is 1/36.
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Larry needs to score 33 points in the last game to have an average of 25 PPG.
To find the answer, we can solve the equation:
<em />(where <em>p</em> is how many points he needs to score in the last game)
To find the mean of a group of numbers, you add them all up and divide the total by the number of numbers there are. Since Larry averaged 23 PPG in 4 games, we can multiply 23 by 4 to get the total of the first 4 games from the data. Then, we find <em>p</em>, which we will add to get our final total. Then, you divide by the 5 games.
First, I simplified 4 x 23 to get 92. Then, I multiplied each side by 5 to get rid of the denominator. Finally, I subtracted 92 from each side to isolate <em>p</em>, and found that <em>p</em> = 33.
To find the answer, we can solve the equation:
<em />(where <em>p</em> is how many points he needs to score in the last game)
To find the mean of a group of numbers, you add them all up and divide the total by the number of numbers there are. Since Larry averaged 23 PPG in 4 games, we can multiply 23 by 4 to get the total of the first 4 games from the data. Then, we find <em>p</em>, which we will add to get our final total. Then, you divide by the 5 games.
First, I simplified 4 x 23 to get 92. Then, I multiplied each side by 5 to get rid of the denominator. Finally, I subtracted 92 from each side to isolate <em>p</em>, and found that <em>p</em> = 33.