Now, he wants to wrap it with wrapping paper. If the length of the shoebox measures 10 in, the width measures 5 in, and the heig
ht measures 3 in, how much wrapping paper does he need to cover the shoebox?
1 answer:
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Surface area is just the area of all these 4 triangles plus the rectangle.
First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together:
First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together: