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Sunny_sXe [5.5K]
2 years ago
7

Use the given graph to determine the limit, if it exists. (4 points)

Mathematics
1 answer:
Zina [86]2 years ago
6 0

The limit as x approaches three from the right of f(x)  is 3

<h3>What is the Limit of a function ?</h3>

The value a function approaches when the variable approaches its limit.

A graph is given which shows a piece  wise function ,

As when the limit approaches from the right the function can be seen approaching 3 , it is not 3 at 3 but approaching to 3

The right hand lim x--> 3 f(x)  approaches  3 .

Therefore , limit as x approaches three from the right of f(x)  is 3

To know more about Limit of a function

brainly.com/question/7446469

#SPJ1

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Roger is building a frame for a flower bed. He is using left-over scraps of wood from his garage. He needs a total of 12 feet of
Korolek [52]

Answer:

C. No, because 11.34 < 12

Step-by-step explanation:

3.14 + 4.12 + 4 has to be greater than or equal to 12

solve the equation

3.14 + 4.12 + 4 >= 12

7.26 + 4 >= 12

11.26 >= 12 is false

I don't know why it says 11.34 because the numbers don't add up, so I'll assume that there is a typo somewhere.

6 0
3 years ago
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

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Answer:

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Step-by-step explanation:

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Dvinal [7]

Answer:

The radius is 25 cm

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V

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