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Andre45 [30]
2 years ago
5

please please in a survey it was found that the ratio of people who like arithmetic and algebra is 9:8 if 25% like both 80% like

none of these and 20% like arithmetic only find the number of people who participate in the survey​
Mathematics
1 answer:
stiks02 [169]2 years ago
7 0

Answer:

200

Step-by-step explanation:

it was found that the ratio of people who liked Arithmetic and Algebra is 9 : 8. If 25% liked the both, 80 liked none of these and 20% liked arithmetic only, find the total number of people participated in the survey. Ans: 200

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Find an​ nth-degree polynomial function with real coefficients satisfying the given conditions.
lesya692 [45]

Answer:

\displaystyle f(x) = -2(x-2)(x^2+4)

Step-by-step explanation:

We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.

First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.

Hence, we will have the three factors:

\displaystyle f(x) = a(x-(2))(x-(2i))(x-(-2i))

Where <em>a</em> is the leading coefficient.

Expand and simplify the second and third factors:

\displaystyle \begin{aligned} (x-(2i))(x-(-2i)) &= (x-2i)(x+2i) \\ \\ &= x(x-2i)+2i(x-2i) \\ \\ &= (x^2 - 2ix) + (2ix - 4i^2) \\ \\ &=x^2 + 4\end{aligned}

Hence:

\displaystyle f(x) = a(x-2)(x^2+4)

Since f(-1) = 30:

\displaystyle \begin{aligned}  f(x) &= a(x-2)(x^2+4) \\ \\ (30) &= a((-1)-2)((-1)^2+4) \\ \\ 30 &= -15a \\ \\ a&= -2\end{aligned}

In conclusion, third degree polynomial function is:

\displaystyle f(x) = -2(x-2)(x^2+4)

5 0
3 years ago
What is 6x(-496)=19x12
vichka [17]

Answer:

-19/248

Step-by-step explanation:

4 0
3 years ago
Please rply asap brainliest
Ira Lisetskai [31]

Answer:

x = 99,53633682

Step-by-step explanation:

sin(34) = x/178

x = sin(34)×178

x = 99,53633682

3 0
3 years ago
1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0
3 years ago
In ΔGHI, the measure of ∠I=90°, the measure of ∠H=52°, and HI = 63 feet. Find the length of IG to the nearest tenth of a foot.
AveGali [126]

Answer:

80.6

Step-by-step explanation:

5 0
3 years ago
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