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Zielflug [23.3K]
3 years ago
6

All of the following statements are true of hydroelectric power EXCEPT: A. Hydroelectric power stations rely on dams to help har

ness the energy of moving water. B. The water within hydroelectric power stations will transfer energy from gravitational potential energy to kinetic energy. C. Hydroelectric power stations can only produce enough energy for a small town as they do not produce large quantities of energy. D. Hydroelectric power stations are very reliable source of energy.
Physics
2 answers:
Artist 52 [7]3 years ago
5 0
The correct answer should be C. Hydroelectric power stations can only produce enough energy for a small town as they do not produce large quantities

Hydroelectric power stations can power even large cities that have millions of people.
kicyunya [14]3 years ago
3 0
In my opinion, the correct answer among the choices listed above is option C. <span>Hydroelectric power stations cannot only produce enough energy for a small town as they do produce large quantities of energy for a large area. Hope this answers the question.</span>
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Answer:

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A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-
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Answer:

The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

Explanation:

Given that,

Velocity of ship = 2.00 m/s due south

Velocity of boat = 5.60 m/s due north

Angle = 19.0°

We need to calculate the component

The velocity of the ship in term x and y coordinate

v_{s_{x}}=0

v_{s_{y}}=2.0\ m/s

The velocity of the boat in term x and y coordinate

For x component,

v_{b_{x}}=v_{b}\cos\theta

Put the value into the formula

v_{b_{x}}=5.60\cos19

v_{b_{x}}=5.29\ m/s

For y component,

v_{b_{y}}=v_{b}\sin\theta

Put the value into the formula

v_{b_{y}}=5.60\sin19

v_{b_{y}}=1.82\ m/s

We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat

For x component,

v_{sb_{x}}=v_{s_{x}}-v_{b_{x}}

Put the value into the formula

v_{sb_{x}=0-5.29

v_{sb}_{x}=-5.29\ m/s

For y component,

v_{sb_{y}}=v_{s_{y}}-v_{b_{y}}

Put the value into the formula

v_{sb_{x}=2.-1.82

v_{sb}_{x}=0.18\ m/s

Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

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