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azamat
3 years ago
11

How do I find frictional force with force applied?

Physics
1 answer:
lions [1.4K]3 years ago
8 0

Answer: Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N.

Determine the friction coefficient.

Multiply these values by each other: 250 N * 0.13 = 32.5 N .

You just found the force of friction!

Explanation:

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Why might a scientist repeat an experiment if she did not make a mistake in the first one?
iren2701 [21]

Answer:

B

Explanation:

4 0
3 years ago
An object of 4 kg has a speed of 6 m/s and moves a distance of 8 m. What is its kinetic energy in joules.
11Alexandr11 [23.1K]

Answer:

The answer to your question is Ke = 72 J

Explanation:

Kinetic energy depends on the speed of and object and its mass.

Data

mass = m = 4 kg

speed = v = 6 m/s

distance = d =  8 m

Kinetic energy = ke = ?

Formula

Ke = (1/2) mv²

Substitution

Ke = (1/2) (4)(6)²

Simplification

Ke = (1/2)(4)(36)

Ke = (1/2)(144)

Ke = 72 Joules

Result

Ke = 72 J

3 0
3 years ago
How much work is required to lift a 2 kg mass to a height of 10 meters?
scoray [572]
Use the equation potential energy =m*g*h
m-mass,
g-gravitational acceleration,
h-height
Potential energy = 2*10*10
=200
kg {m}^{2}   {s}^{ - 2}
This is the unit of the energy
6 0
3 years ago
A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh
vesna_86 [32]

Answer:t=0.1205

Explanation:

Given

Refractive index of oil\left ( \mu \right )=1.4

Wavelength of red light =675 mm

Condition for constructive interference is

2\mu _{oil}t=\frac{m\lambda }{2}

t=\frac{m\lambda }{4\mu _{oil}}

For m= 1 i.e. for minimum thickness

t=\frac{1\times 675\times 10^{-9}}{4\times 1.4}

t=0.1205 \mu m

5 0
3 years ago
A car is traveling at 40 m/s. The brakes are applied an after 3 seconds the car is traveling 13 m/s. What is the acceleration of
Elena-2011 [213]

Answer:

- 9m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Time taken  = 3s

Final velocity  = 13m/s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time taken.

   Acceleration  = \frac{Final velocity  - Initial velocity }{Time taken}  

  Acceleration  = \frac{13  - 40 }{3}   = - 9m/s²

4 0
3 years ago
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