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3 years ago

How do I find frictional force with force applied?

Physics

1 answer:

lions [1.4K]3 years ago

8 0

Answer: Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N.

Determine the friction coefficient.

Multiply these values by each other: 250 N * 0.13 = 32.5 N .

You just found the force of friction!

Explanation:

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If two variables have a non-related relationship and one of the variables is changed, how will the other variable change?

PolarNik [594]

If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.

None of the choices says this.

6 0

3 years ago

How do electromagnetic forces work?

zlopas [31]

It attracts two charged particles which are separated by a definitive distance.......

4 0

4 years ago

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the

marysya [2.9K]

Answer:

Explanation:

1 ) the volume of helium in the balloon when fully inflated

= 4/3 π R³

= 4/3 x 3.14 x 5.3³

= 623.3 m³

2 ) force of gravity on the entire system ,but with no people

= (mass of the empty balloon and basket + mass of helium )x g

=( 129 + 623.3 x.18 )x 9.8

= 2363.7 N

3 ) magnitude of the buoyant force on the entire system (but with no people )

( Volume of empty balloon + basket + volume of helium ) density of air x g

( 0.057 + 623.3 ) x 1.23 x 9.8

= 7513.94 N

4 ) magnitude of the force of gravity on each person

Mass of each person x g

= 71 x 9.8

= 695.8 N

6 0

3 years ago

A film of oil that has an index of refraction of 1.45 rests on an optically flat piece of glass of index of refraction n = 1.60.

blagie [28]

Answer:

442.75862 nm

Explanation:

m = Order

n = Refractive index

$\lambda$ = Wavelength

We have the relation of thickness and wavelength given by

$2nt=m\lambda$

The consecutive spectral line is given by

$2nt=(m+1)\lambda$

So,

$\lambda=\dfrac{2nt}{m}\\\Rightarrow 642=\dfrac{2nt}{m}$

and

$428=\dfrac{2nt}{m+1}$

Dividing the wavelengths we get

$\dfrac{642}{428}=\dfrac{m+1}{m}\\\Rightarrow 1.5 m=m+1\\\Rightarrow m=\frac{1}{0.5}\\\Rightarrow m=2$

$t=\dfrac{m\lambda}{2n}\\\Rightarrow t=\dfrac{2\lambda}{2n}\\\Rightarrow t=\dfrac{642}{1.45}\\\Rightarrow t=442.75862\ nm$

The film thickness of oil is 442.75862 nm

8 0

4 years ago

Air enters a 28-cm diameter pipe steadily at 200 kPa and 20°C with a velocity of 5 m/s. Air is heated as it flows and leaves the

abruzzese [7]

Answer:

The mass flow rate of air is 0.732 kg/s.

The velocity at the exit is 5.927 m/s.

Explanation:

Given that,

Diameter = 28 cm

Enter pressure= 200 kPa

Enter temperature = 20°C

Velocity = 5 m/s

Exit pressure = 180 kPa

Exit temperature = 40°C

We need to calculate the mass flow rate of air

Using formula of mass flow rate

$\dot{m}=\rho\times \dot{V}$

$\dot{m}=\dfrac{P}{RT}\times A\times v$

Put the value into the formula

$\dot{m}=\dfrac{200}{0.287\times293}\times\dfrac{(0.28)^2}{4}\times\pi\times5$

$\dot{m}=0.732\ kg/s$

We need to calculate the volume flow rate

Using formula of volume flow rate

$\dot{V'}=\dfrac{\dot{m}}{\rho'}$

$\dot{V'}=\dfrac{RT'\dot{m}}{P'}$

$\dot{V'}=\dfrac{0.287\times313\times0.732}{180}$

$\dot{V'}=0.365\ m^3/s$

We need to calculate the velocity at the exit

Using formula of velocity

$v'=\dfrac{\dot{V'}}{A}$

Put the value into the formula

$v'=\dfrac{4\times0.365}{(0.28)^2\times\pi}$

$v'=5.927\ m/s$

Hence, The mass flow rate of air is 0.732 kg/s.

The velocity at the exit is 5.927 m/s.

4 0

3 years ago