Answer:
18.5 m/s
Explanation:
On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:

where
is the coefficient of static friction between the tires and the road
m is the mass of the car
g is the gravitational acceleration
v is the speed of the car
r is the radius of the curve
Re-arranging the equation,

And by substituting the data of the problem, we find the speed at which the car begins to skid:

Answer:
9.8N
Explanation:
Here we can get gravitational acceleration according to the place where object is placed by bellow equation
g = GM/R²
g - Gravitational Acceleration
G - Gravitational constant (6.67×10-11)
R - Distance ( Radius )
g = 6.67 × 10-11 × 1024 /(6.37×106)²
g = 9.8 m/s²
There for
Weight = Mass × Gravitational acceleration
= 1×9.8
= 9.8 N
Air resistance fefrgtdnjrcbrdg
Determined by cross product or ( vector product )