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3 years ago

Which items are matter? Battery electricity mobile phone sound light heat

Physics

2 answers:

Margaret [11]3 years ago

8 0

Explanation:

Matter is defined as any object which occupies space and has volume.

A substance that is present in solid, liquid or gaseous state will be considered as a matter.

For example, a chair is a solid substance and hence it is a matter.

Whereas electricity is the flow of charges, sound, light and heat are all due to exchange of energy. Hence, they are not matter.

Thus, we can conclude that out of the given options battery and mobile phone are matter.

algol [13]3 years ago

4 0

BAttery mobile phone

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A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?

Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

$I=\frac{Q}{t}$

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

I= 19500 A
Q=36 C
t=?

Replacing:

$19500 A=\frac{36 C}{t}$

Solving:

19500 A*t= 36 C

$t=\frac{36 C}{19500 A}$

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

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3 years ago

Which of the following is a simple machine? A. wedge B. meat grinder C. car D. bicycle

kati45 [8]

I think the answer is D. Bicycle

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3 years ago

Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa

lyudmila [28]

Answer:

No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field $\vec{E}$ is related to the gradient of the electric potential V with :

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})$

This means that for constant electric potential the electric field must be zero:

$V(\vec{r}) = k$

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k$

$\vec{E} (\vec{r}) = - (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k$

$\vec{E} (\vec{r}) = - (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})$

$\vec{E} (\vec{r}) = - (0,0,0)$

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

$V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4$

give an electric field of zero at point (0,0,0)

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3 years ago

The period P of a pendulum depend on its length , mass as well as the acceleration due to gravity . Use dimensional analysis to

Savatey [412]

Explanation:

Period P has units of seconds (s).

Length has units of meters (m).

Mass has units of kilograms (kg).

Acceleration has units of meters per second squared (m/s²).

Dimensional analysis:

s = √(m / (m/s²))

Therefore:

P = k √(L/g)

where k is a dimensionless constant.

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3 years ago

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as show

Grace [21]

Answer:

pretty sure its motor 2, with body 1

Explanation:

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3 years ago

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