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vredina [299]
2 years ago
12

An object on Earth weighs 150 N. What is its mass?

Physics
1 answer:
Alex777 [14]2 years ago
3 0

Answer:

\tt \: mass \:  =  \frac{weight}{acceleration \: due \: to \: gravity}

\longrightarrow \tt \:  \frac{150}{10}

\longrightarrow \boxed{ \tt{15 \: kg}}

  • Our final answer is 15 kg .

----------- HappY LearninG<3 ------------

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A hollow plastic sphere is held below the surface of a fresh-water lake by a cord anchored to the bottom of the lake. The sphere
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Answer: a) B = 6811N

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Explanation: <em>Buoyant force</em> is a force a fluid exerts on a submerged object.

It can be calculated as:

B=\rho_{fluid}.V_{obj}.g

where:

\rho_{fluid} is density of the fluid the object is in;

V_{obj} is volume of the object;

g is acceleration due to gravity, is constant and equals 9.8m/s²

a) For the hollow plastic sphere, density of water is 1000kg/m³:

B=10^{3}.0.695.9.8

B = 6811N

b) Anchored to the bottom, the forces acting on the sphere are <u>Buoyant</u>, <u>Tension</u> and <u>Force due to gravity</u>:

B = T + F_{g}

B = T + mg

mg = B - T

m=\frac{B - T}{g}

Calculating:

m=\frac{6811 - 900}{9.8}

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c) When the shpere comes to rest on the surface of the water, there are only <u>buoyant</u> <u>and</u> <u>gravity</u> acting on it:

B = m.g

\rho_{w}.V_{sub}.g=m.g

V_{sub}=\frac{m}{\rho_{w}}

V_{sub}=\frac{603.2}{1000}

V_{sub} = 0.6032m³

Fraction of the submerged volume is:

\frac{V_{sub}}{V_{obj}} = \frac{0.6932}{0.695} = 0.868

<u />

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3 years ago
A bowling ball is on the end of a rope of length 5 meters, the other end of which is attached to a hook in the ceiling. The ball
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m\cdot g \cdot \sin \theta = m\cdot a

g\cdot \sin \theta = a

a = 0\,\frac{m}{s^{2}}

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