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Len [333]
3 years ago
7

What is a scientist studying if she is interested in the flow of energy, heat, and work?

Physics
2 answers:
padilas [110]3 years ago
8 0
<span>is D. Thermodynamics</span>
Arte-miy333 [17]3 years ago
6 0
D thermodynamic is right
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Find the minimum radius of a helium balloon that will lift her off the ground. the density of helium gas is 0.178 kg/m3, and the
marysya [2.9K]

Volume of balloon = \frac{4}{3} \pi r^{3}

Where r is the radius of balloon.

Here mass of woman = 68 kg

Mass of air displaced by a balloon with volume V = 1.29*V

Mass of helium inside balloon = 0.178*V

Total mass to be lifted by balloon = 68 +0.178*V

Buoyant force = 1.29V-0.178V=1.112V

So we have 1.112 V =  68+ 0.178*V

   0.934 V = 68

     V = 72.81 m^3

    \frac{4}{3} \pi r^{3}[/tex]= 72.81

     r = 2.59 m

So radius of helium balloon = 2.59 m

4 0
3 years ago
The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum
kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20×10^{-2}\ \mu F.

We need to calculate the resonance frequency

Using formula of frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.88\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi\times f\times C\times V_{c}

I=2\pi\times2356.88\times1.20\times10^{-8}\times590

I=0.1048\ A

Impedance of the circuit is

z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}

At resonance frequency X_{L}=X_{C}

Z=R

We need to calculate the maximum voltage

Using ohm's law

V=I\times R

V=0.1048\times400

V=41.92\ V

Hence, The maximum voltage is 41.92 V.

4 0
3 years ago
Which type of bond (ionic, covalent, or metallic) does the phrase "opposite attract" apply to best? Explain.
snow_tiger [21]
Ionic is where the bonding of elements attract opposites
6 0
3 years ago
Read 2 more answers
After a great many contacts with the charged ball, how is the charge on the rod arranged (when the charged ball is far away)?
faust18 [17]

Answer: Option (b) is the correct answer.

Explanation:

Since, there is a negative charge present on the ball and a positive charge present on the rod. So, when the negatively charged metal ball will come in contact with the rod then positive charges from rod get conducted towards the metal ball.

Hence, the rod gets neutralized. But towards the metal ball there is a continuous supply of negative charges. Therefore, after the neutralization of positive charge from the rod there will be flow of negative charges from the metal ball towards the rod.

Thus, we can conclude that negative charge spread evenly on both ends.

8 0
3 years ago
PLEASE ANSWER ASAP!!!
Mice21 [21]

The total momentum of the system has to be conserved to satisfy the principle of conservation of momentum. Before the ball hits the bottle, the momentum of the system is 0.4 x 18 = 7.2 kg m/s

The momentum of the bottle after being hit is 0.2 x 25 = 5 kg m/s

So the momentum of the ball now is 7.2 - 5 = 2.2 kg m/s

Hence its velocity is 2.2/0.4 = 5.5 m/s

3 0
3 years ago
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