Distance = 0.5 x g x t^2 where g is the gravitational force and t is the time required to cover the mentioned distance.
we have g = 9.8 m/sec^2 and distance = 16 cm = 0.16 m
From the above mentioned equation:
t = (2s / g)^0.5
Substituting with the givens, we can calculate t as follows:
t = [(2 x 0.16) / 9.8]^0.5 = 0.1807 seconds
The radius and time period of orbit of a sattellite are related by the formula:
R³ = GMT²/4π²; where R is the orbital radius, T is the orbital time period, M is the mass of the more massive body, G is the graviational constant
(9.4 x 10⁶)³ = (6.674 × 10⁻¹¹<span>)(M)(2.8 x 10</span>⁴<span>)</span>²<span> / (4</span>π²)
M = 6.27 x 10²³ kg
Hello!
Pure water has a density of 0.99823<span> grams or cubic centimeter at 1 atm pressure and a temperature around 68 degrees Fahrenheit.
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Or it can just be known as <span>1 g/cm³
Hoped this helped c;
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Answer:
Explanation:
Speed of electron
v = 4 × 10^5 •j m/s
Magnetic field
B = 5 × 10^-5 T at angle of 45° to horizontal
Charge of electron
q = 1.6 × 10^-19C
Magnitude of force F?
The Force exerted in an electric field is given as
F = q(v×B)
Now, x component of the magnetic field
Bx = BCos45 = 5×10^-5 Cos45
Bx = 3.54 × 10^-5 •i T
Also, y component
By = BSin45 = 5 × 10^-5Sin45
By = 3.54 × 10^-5 •j T
B = 3.54 × 10^-5 •i + 3.54 × 10^-5 •j T
Now, F = q(v×B)
Note that,
i×i=j×j=k×k=0
i×j =k, j×k = i, k×i = j
j×i = -k, k×j = -i and i×k = -j
Therefore
F = q(v×B)
F = 1.6×10^-19(4×10^5•j × (3.54 × 10^-5 •i + 3.54 × 10^-5 •j T))
F = 1.6×10^-19 (4×10^5 × 3.54 × 10^-5 (j×i) + 4×10^5 × 3.54 × 10^-5(j×j))
F = 1.6×10^-19(14.14(-k) + 0)
F = —2.26 × 10^-18 •k N
It is in the negative direction of z axis
The magnitude of the force the field experience is 2.26 × 10^-18 N