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Lemur [1.5K]
3 years ago
12

A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 12.0 m/s and accelerates

at the rate of 0.650 m/s2 for 7.00 s. (a) What is his final velocity (in m/s)?
Physics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

Final speed of the racer, v = 16.55m/s

Explanation:

It is given that,

Initial velocity of the racer, u = 12 m/s

Acceleration, a=0.65\ m/s^2

time taken, t = 7 s

We need to find the final velocity of the racer. Let it is given by v. It can be calculated using first equation of motion as :

v=u+at

v=12+0.65\times 7

v = 16.55 m/s

So, the final speed of the racer is 16.55 m/s. Hence, this is the required solution.

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The bulk of the world's deserts are located at 30 degrees north latitude and 30 degrees south latitude, when the warm equatorial air begins to descend. The heavy, warm, descending air vaporises large amounts of water from the ground's surface. As a result, the environment is rather dry.

<h3>Why are the majority of the desert regions on Earth located between 20 and 30 degrees latitude?</h3>

The zones of falling air are those between 20 and 30 latitudes on the western borders of continents (high pressure and dry weather). As a result, the moisture continues to decrease as the air is compressed and warmed as it falls.

Where the scorching equatorial air starts to descend, the majority of the world's deserts are found between 30 degrees north and 30 degrees south latitude. Large volumes of water are vaporised off the surface of the ground by the thick, warming, falling air. As a result, the climate is extremely dry.

Learn more about latitude refer

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1 year ago
What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coeff
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The net force on the object as described is; 58.84N

Two forces acting on the object are;

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In essence; the frictional force can be evaluated as;

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  • Frictional force = 0.21 × 20 × 9.8.

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4. A 1,000-kilogram satellite completes a uniform circular orbit of radius 8.0 x 10 meters as
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Answer:

Zero

Explanation:

The work done by a force on an object is given by:

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F is the magnitude of the force

d is the displacement of the object

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In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so \theta=90^{\circ} and cos \theta =0. Therefore, the work done by gravity is also zero.

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jeka94

Answer:

All of these answers are dependent upon the specific scenario, but here are some general answers.

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3. Depends on what scenario your class had.

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