Answer:
Final speed of the racer, v = 16.55m/s
Explanation:
It is given that,
Initial velocity of the racer, u = 12 m/s
Acceleration,
time taken, t = 7 s
We need to find the final velocity of the racer. Let it is given by v. It can be calculated using first equation of motion as :
v = 16.55 m/s
So, the final speed of the racer is 16.55 m/s. Hence, this is the required solution.
The potential energy of the block is A) 490 J
Explanation:
The potential energy of an object is the energy possessed by the object due to its position in the gravitational field.
It is calculated as follows:
where
m is the mass of the object
g is the acceleration due to gravity
h is the height of the object above the ground
For the block in this problem, we have:
m = 10 kg
h = 5 m
Therefore, its potential energy is:
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Answer:
44 N
Explanation:
The electrostatic forces between two charges is given by:
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is their separation
We notice that the force is directly proportional to the charges.
In this problem, initially we have a force of
F = 22 N
on a q2 = 4.0 C, exerted by a charge q1.
If the charge is doubled,
q2 = 8.0 C
This means that the force will also double, so it will be