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bogdanovich [222]
3 years ago
15

Examples of Laws Of Motion

Physics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

Explanation:

1. The law that best illustrate this is Newton's first law of motion, which is also called the law of inertia

The law states that every object will continue in the sate of rest or in uniform motion except it is acted upon by an external force. The bike stop moving because it hits a curb.

Inertia: This is the reluctance or the tendency for a body to be in its state of rest or uniform motion.

And Maya is thrown into the air due to it inertia.

2. The Law that best illustrate this is Newton's  Third law of motion.

This law states that to every action there is an equal and opposite reaction.

As the bird uses his wind to push air downward, air pushes upward on the bird allows it to fly. the upward and downward movement of air are both equal but opposite reaction.

3. The Law that illustrate this is Newton's second law of motion.

This law can be summarize as force is directly proportional to mass and acceleration.

Because the mass of the second box is smaller than the first box that was why its accelerate at a greater rate.

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denis-greek [22]
Sound waves the force of said sound wave would knock you backwards

8 0
3 years ago
You did 200 joules of work lifting a 150-newton backpack. How high did you lift the backpack?
kaheart [24]
We know that:
W=Fs
200J=150N*s
s=200J/150N
s=1,33m
8 0
3 years ago
A truck, initially at rest, rolls down a frictionless hill and attains a speed of 20 m/s at the bottom. To achieve a speed of 40
Crank

Answer:

To achieve the velocity of 40 m/sec height will become 4 times  

Explanation:

We have given initially truck is at rest and attains a speed of 20 m/sec

Let the mass of the truck is m

At the top of the hill potential energy is mgh and kinetic energy is \frac{1}{2}mv^2

So total energy at the top of the hill =mgh+0=mgh

At the bottom of the hill kinetic energy is equal to \frac{1}{2}mv^2 and potential energy will be 0

So total energy at the bottom of the hill is equal to 0+\frac{1}{2}mv^2

Form energy conservation mgh=\frac{1}{2}mv^2

v=\sqrt{2gh}, for v = 20 m/sec

20=\sqrt{2\times 9.8\times h}

Squaring both side

19.6h=400

h = 20.408 m

Now if velocity is 0 m/sec

40=\sqrt{2gh}

19.6h=1600

h = 81.63 m

So we can see that to achieve the velocity of 40 m/sec height will become 4 times

5 0
3 years ago
Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t
Elenna [48]

Answer:

The vector equation of the line is

                                \overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

Explanation:

The vector equation of the line is given by

                                     r(t) = r_{o} + tv

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

8 0
3 years ago
2 kg
pochemuha

Answer:

2500 and kg its is very easy do with method

8 0
3 years ago
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