For this case we have that by definition, the density is given by:

Where:
M: It is the mass
V: It is the volume
According to the data of the statement we have:

So, the mass is given by:

Thus, the mass of the brass ornament is
Answer:

He must work 13 hours. I don't feel like showing my work.
A, C, and E.
you can check them by putting into y=mx+b form. if m is negative then as domain increases range decreases.
Answer:
2x^2 +11
Step-by-step explanation:
f(x) = 3x^2 + 2 and g(x) = x^2 – 9
(f – g)(x) = 3x^2 + 2 -( x^2 – 9)
Distribute the minus sign
3x^2 + 2 - x^2 + 9
Combine like terms
2x^2 +11