Answer:
35.7%
Explanation:
The percent yield is calculated by the formula:
<em>[(actual yield) / (theoretical yield)] * 100</em>
In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:
Thus, the percent yield of is 35.7%.
Hope this helps!
The mass of impure is 20.7167 g. The decomposition reaction is as follows:
Here, 1 mole of gives 1 mole of MgO.
Molar mass of and MgO is 84.31 g/mol and 40.3044 g/mol respectively.
Converting number of moles in terms of mass,
Here, M is molar mass.
Since,
Thus,
On putting the values,
Rearranging,
Or,
...... (1)
Let the mass of impurity be and mass of impure
is 20.7167 g thus,
...... (2)
Also, mass of impure MgO is 16.8817 g thus,
...... (3)
On comparing equations (2) and (3),
Putting the value of in equation (1),
Or,
Or,
Or,
Or,
Thus, magnesium carbonate present in the original sample is 7.35 g.