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3 years ago

9

What would happen if you added more than 5ml of H2O2 to the 5ml of yeast

2 answers:

Jlenok [28]3 years ago

8 0

Answer:

More water and oxygen is produced.

Explanation:

In an experiment which consist of mixing H2O2 with yeast the following reaction occurs:

2 H2O2 -> 2 H2O + 02

Yeast acts as a catalyst, i.e. makes the reaction faster.

The bigger amount of H2O2 you add, the bigger amount of water and oxygen you produce.

anzhelika [568]3 years ago

7 0

Hydrogen peroxide breaks down into water and oxygen.

2H₂O₂ → 2H₂O + O₂

The yeast present contains an enzyme called catalase which catalyses the reaction.

More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.

Thus if we added more than 5 mL of yeast solution to the 2H₂O₂, the breakdown would occur faster. Thus the bubbles and the accompanying fizz would be much more.

Read more on Brainly.com - brainly.com/question/10670134#readmore

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This is the chemical formula for carvone (the chemical that gives spearmint its flavor): An organic chemist has determined by me

xz_007 [3.2K]

The given question is incomplete. The complete question is :

This is the chemical formula for carvone (the chemical that gives spearmint its flavor) $C_{10}H_{14}O$ : An organic chemist has determined by measurements that there are 27.3 moles of carbon in a sample of carvone. How many moles of oxygen are in the sample

Answer: 2.73 moles of oxygen are there in the sample.

Explanation:

The chemical formula of carvone is $C_{10}H_{14}O$ .

This means:

When 10 moles of carbon are there in carvone , 1 mole of oxygen is there in carvone

Thus for 27.3 moles of carbon in carvone , $\frac{1}{10}\times 27.3=2.73$ mole of oxygen is there in carvone.

Thus 2.73 moles of oxygen are there in the sample.

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2 years ago

Ferris & Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.

DIA [1.3K]

Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: <u>For MnO₄⁻ solution</u>-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

<u>For Fe²⁺ solution</u>:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

<u><em>To find out the concentration of Fe²⁺ solution (M₂), we use the equation:</em></u>

$\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}$

$\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}$

$0.505 = M_{2}\times 3$

$M_{2} = \frac{0.505}{3} = 0.168M$

<u>Therefore, the concentration or molarity of Fe²⁺ solution: </u><u>M₂ = 0.168 M</u>

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Answer:

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Nadusha1986 [10]

Answer:

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