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3 years ago

What would happen if you added more than 5ml of H2O2 to the 5ml of yeast

Chemistry

2 answers:

Jlenok [28]3 years ago

8 0

Answer:

More water and oxygen is produced.

Explanation:

In an experiment which consist of mixing H2O2 with yeast the following reaction occurs:

2 H2O2 -> 2 H2O + 02

Yeast acts as a catalyst, i.e. makes the reaction faster.

The bigger amount of H2O2 you add, the bigger amount of water and oxygen you produce.

anzhelika [568]3 years ago

7 0

Hydrogen peroxide breaks down into water and oxygen.

2H₂O₂ → 2H₂O + O₂

The yeast present contains an enzyme called catalase which catalyses the reaction.

More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.

Thus if we added more than 5 mL of yeast solution to the 2H₂O₂, the breakdown would occur faster. Thus the bubbles and the accompanying fizz would be much more.

Read more on Brainly.com - brainly.com/question/10670134#readmore

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Which equation represents a conservation of atoms? Group of answer choices LaTeX: 4Fe\:+3O_2\:\longrightarrow\:2Fe_2O_3 4 F e +

slamgirl [31]

Answer : The equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Explanation :

Law of conservation of matter : It states that matter can neither be created nor be destroyed but it can only be transformed from one form to another form.

The balanced chemical reaction always follow the law of conservation of matter.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

(1) The given chemical reaction is,

$4Fe+3O_2\rightarrow 2Fe_2O_3$

This reaction is a balanced chemical reaction in which number of atoms of iron and oxygen are equal on the both side of the reaction. So, this reaction obey the law of conservation of matter.

(2) The given chemical reaction is,

$2Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of iron and oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

(3) The given chemical reaction is,

$4Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

Hence, the equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

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2 years ago

Why do tropical cyclones spawn around ? please include 5 sentences

BaLLatris [955]

Bc they dooooooooooooooooooo

4 0

3 years ago

How many metals, nonmetals and metalloids are there in the periodic table?

Ugo [173]

Answer:

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6 0

2 years ago

Read 2 more answers

Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t

Liono4ka [1.6K]

Answer: The value of $K_{b}$ for chloroform is $3.62^{o}C/m$ when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

$\Delta T_{b} = 3.80^{o}C$

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

$Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m$

Now, the values of $K_b$ is calculated as follows.

$\Delta T_{b} = i\times K_{b} \times m$

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

$K_{b}$ = molal boiling point elevation constant

Substitute the values into above formula as follows.

$\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m$

Thus, we can conclude that the value of $K_{b}$ for chloroform is $3.62^{o}C/m$ when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0

3 years ago

Can u answer all of em

TiliK225 [7]

Answer:

one is across

Explanation:

8 0

2 years ago