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Fiesta28 [93]
3 years ago
14

15 grams of HCl should theoretically produce 0.42 grams of H2. The reaction actually produced 0.15 grams of H2. What is the perc

entage yield of H2?
Steps to solution please
Chemistry
1 answer:
Helen [10]3 years ago
8 0

Answer:

35.7%

Explanation:

The percent yield is calculated by the formula:

<em>[(actual yield) / (theoretical yield)] * 100</em>

In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:

\frac{0.15}{0.42} *100=0.357*100=35.7

Thus, the percent yield of H_2 is 35.7%.

Hope this helps!

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What are the products of the balanced equation for the combustion of C8H17OH ?
erastova [34]
C8H17OH + 12O2 —> 8CO2 + 9H2O
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An unknown acid solution has PH 3.4. 66% of the acid is ionized. Whats the pka?
juin [17]

Answer:

pKa=3.58

Explanation:

Hello,

In this case, since the pH defines the concentration of hydrogen:

pH=-log([H^+])

[H^+]=10^{-pH}=10^{-3.4}=3.98x10^{-4}

And the percent ionization is:

\% \ ionization=\frac{[H^+]}{[HA]}*100\%

We compute the concentration of the acid, HA:

[HA]=\frac{[H^+]}{\% \ ionization}*100\%=\frac{3.98x10^{-4}}{66\%}  *100\%\\\\

[HA]=6.03x10^{-4}

Thus, the Ka is:

Ka=\frac{[H^+][A^-]}{[HA]}=\frac{3.98x10^{-4}*3.98x10^{-4}}{6.03x10^{-4}}\\  \\Ka=2.63x10^{-4}

So the pKa is:

pKa=-log(Ka)=-log(2.63x10^{-4})\\\\pKa=3.58

Regards.

5 0
3 years ago
Solve fasttt<br><br> C7H17+O2=CO2+H2O<br><br> Balancing Equations
sertanlavr [38]

Answer:

The answer to your question is

                                        4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

Explanation:

Write the equation

                                        C₇H₁₇  +    O₂    ⇒    CO₂   +    H₂O  

Process

1.- Check if the equation is balanced

                                 Reactants            Element              Products

                                        7                          C                           1

                                       17                          H                          2

                                        2                          O                          3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂   and a coefficient of 17/2 to H₂O

                                      C₇H₁₇  +    O₂    ⇒   7CO₂   +  \frac{17}{2}H₂O  

                                 Reactants            Element              Products

                                        7                          C                           7

                                       17                          H                          17

                                        2                          O                          51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

                         4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

                  Reactants            Element              Products

                        28                          C                        28

                        68                          H                        68

                        90                          O                        90

5 0
3 years ago
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