Did you ever get the awnser to this question cause im stuck on it too
Answer:
Ksp = 3.24 x 10⁻⁴
Explanation:
The dissociation equilibrium for a generic salt AB is:
AB(s) ⇄ A⁺(aq) + B⁻(aq)
s s
For instance, the expression for the Ksp constant is:
Ksp = [A⁺] [B⁻] = s x s = s²
According to the problem, 0.0180 mol of the salt is soluble in 1.00 L os water. That means that the solubility of the salt (s) is equal to 0.0180 mol per liter.
s = moles of solute/L of solution = 0.0180 mol/L
Thus, we calculate Ksp from the s value as follows:
Ksp = s² = (0.0180)² = 3.24 x 10⁻⁴
Answer:
Option B. Sodium
Explanation:
In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:
Na —> Na+ + e- ....... (1)
Cl + e- —> Cl- ......... (2)
Now, combining equation 1 and 2 we have:
Na + Cl + e- —> Na+ + Cl- + e-
Cancelling the electron from both side, we obtained:
Na + Cl —> Na+Cl-
From the above illustration, we see clearly that sodium loses electron
The abundance of isotope 35 = 75%
The abundance of isotope 37 = 25%
Ratio isotope 35 : isotope 37 = 3 : 1
<h3>Further explanation</h3>
Given
Ar Cl = 35.5
Two isotopes of mass number 35 and 37
Required
The ratio of each isotope
Solution
If the abundance of isotope 35 is x%, then the abundance of isotope 37 is (100-x)%
35.5 = x%.35 + (100-x)%.37
35.5 = 0.35x+0.37(100-x)
35.5=0.35x-0.37x+37
0.02x=1.5
x=75
