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3 years ago

If the current is cut in half and the resistance is increased by a factor of three, how will the power be affected?

1 answer:

8 0

One formula for the power dissipated in an electric circuit is

   Power = (current)² x (resistance) .

I think that's the one we should use, because it has exactly
all of the quantities that we know or need to find.

OK.
   Original power = (original current)² x (original resistance)
and
   New power = (new current)² x (new resistance)

   = (0.5 x old current)² x (3 x old resistance)

   = (0.25) (old current)² x (3) (old resistance)

   = (0.75) (original current)² (original resistance)

   = (0.75) (original power) .

Summary: New power = (0.75) (original power)

That looks just like
choice B:
   The power will decrease to 75 percent of its previous value.

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3 years ago

Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.

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$0.5\times 10^{-6}C$

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According to coulombs law force between two charges is given by $F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}$ here R is the distance between both the charges which is given as 25 cm

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