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3 years ago

If the current is cut in half and the resistance is increased by a factor of three, how will the power be affected?

1 answer:

8 0

One formula for the power dissipated in an electric circuit is

   Power = (current)² x (resistance) .

I think that's the one we should use, because it has exactly
all of the quantities that we know or need to find.

OK.
   Original power = (original current)² x (original resistance)
and
   New power = (new current)² x (new resistance)

   = (0.5 x old current)² x (3 x old resistance)

   = (0.25) (old current)² x (3) (old resistance)

   = (0.75) (original current)² (original resistance)

   = (0.75) (original power) .

Summary: New power = (0.75) (original power)

That looks just like
choice B:
   The power will decrease to 75 percent of its previous value.

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Create your own simple metaphor illustrating how demand and supply work together to create equilibrium. Label the following on y

alina1380 [7]

''When the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.''

<h3>How equilibrium occur?</h3>

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So we can conclude that when the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.

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2 years ago

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3 years ago

our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three

Licemer1 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The torque produced by the pile of rocks is $\tau = 35.63\ N \cdot m$

The distance of the single for equilibrium to occur is $r_s =1.62 \ m$

Explanation:

From the question we are told that

The mass of the left rock is $m_s = 2.25 \ kg$

The mass of the rock on the right $m_p = 10.1 kg$

The distance from fulcrum to the center of the pile of rocks is $r_p = 0.360 \ m$

Generally the torque produced by the pile of rock is mathematically represented as

$\tau = m_p * g * r_p$

Substituting values

$\tau = 10.1 * 9.8 * 0.360$

$\tau = 35.63\ N \cdot m$

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

The torque due to the single rock is

$\tau = m_s * g * r_s$

At equilibrium the both torque are equal

$35.63 = m_s * r_s * g$

Making $r_s$ the subject of the formula

$r_s = \frac{35.63 }{m_s * g}$

Substituting values

$r_s = \frac{35.63 }{2.25 * 9.8}$

$r_s =1.62 \ m$

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What is the momentum of a 546,540 kg train that is travelling at 7.8 m/s

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