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masha68 [24]
3 years ago
6

If the current is cut in half and the resistance is increased by a factor of three, how will the power be affected?

Physics
1 answer:
olasank [31]3 years ago
8 0

One formula for the power dissipated in an electric circuit is

         Power  =  (current)² x (resistance) .

I think that's the one we should use, because it has exactly
all of the quantities that we know or need to find.

OK.       
               Original power  =  (original current)² x (original resistance)
and
               New power  =  (new current)²  x  (new resistance)

                                 =  (0.5 x old current)² x (3 x old resistance)

                                 = (0.25) (old current)² x (3) (old resistance)

                                 =  (0.75) (original current)² (original resistance)

                                 =  (0.75) (original power) .

Summary:        New power  =  (0.75) (original power)

That looks just like
choice B: 
                 The power will decrease to 75 percent of its previous value.
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Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Sim
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Answer:

The distance covered by puck A before collision is  z = 8.56 \ m

Explanation:

From the question we are told that

   The label on the two hockey pucks is  A and  B

    The distance between the  two hockey pucks is D   18.0 m

     The speed of puck A is  v_A =  3.90 \ m/s

        The speed of puck B is  v_B  =  4.30 \ m/s

The distance covered by puck A is mathematically represented as

     z =  v_A * t

  =>  t  =  \frac{z}{v_A}

 The distance covered by puck B  is  mathematically represented as

      18 - z =  v_B  * t

=>   t  = \frac{18 - z}{v_B}

Since the time take before collision is the same

        \frac{18 - z}{V_B}  =  \frac{z}{v_A}

substituting values

          \frac{18 -z }{4.3}  = \frac{z}{3.90}

=>      70.2 - 3.90 z   = 4.3 z

=>       z = 8.56 \ m

8 0
3 years ago
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