it has a rocky core so the gravity from that compacts the gases extremly tight
the answer is ( True ) .
the current is the same in series circuits .
Answer:
SURE!!!...
But what to calculate!!!....
1750 meters.
First, determine how long it takes for the kit to hit the ground. Distance over constant acceleration is:
d = 1/2 A T^2
where
d = distance
A = acceleration
T = time
Solving for T, gives
d = 1/2 A T^2
2d = A T^2
2d/A = T^2
sqrt(2d/A) = T
Substitute the known values and calculate.
sqrt(2d/A) = T
sqrt(2* 1500m / 9.8 m/s^2) = T
sqrt(3000m / 9.8 m/s^2) = T
sqrt(306.122449 s^2) = T
17.49635531 s = T
Rounding to 4 significant figures gives 17.50 seconds. Since it will take
17.50 seconds for the kit to hit the ground, the kit needs to be dropped 17.50
seconds before the plane goes overhead. So just simply multiply by the velocity.
17.50 s * 100 m/s = 1750 m
The answer is A. Further apart and move faster.
Conduction in general is the transfer of energy from molecule to molecule through DIRECT CONTACT. In solids and liquids, the molecules are closer to each other; more so in solids than liquids. This enables them to pass energy more quickly. Gas molecules on the other hand are further apart and move faster because they have space to move more freely. Energy does not easily pass on to the next molecule because of the distance between the molecules.
