Answer: 0.4533mol/L
Explanation:
Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol
68g of CaCO3 dissolves in 1.5L of solution.
Xg of CaCO3 will dissolve in 1L i.e
Xg of CaCO3 = 68/1.5 = 45.33g/L
Molarity = Mass conc.(g/L) / molar Mass
Molarity = 45.33/100 = 0.4533mol/L
So that every measurement is accurate.. hope this helps
Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
a heater turns electrical energy into thermal energy
the sun turns gas into thermal energy
annd i cant think of anymore but i hope this helps you
Answer:
The partial pressure of nitrogen is 597.5 torr
Explanation:
Step 1: Data given
Mol fraction of N = 0.781
Mol fraction of O = 0.209
Mol fraction Ar = 0.010
Atmospheric pressure = 765.0 torr
The partial pressure is given by Pi = Xi * Pt
⇒ χ
i = the mole fraction of gas i in the mixture
⇒ P
total = the total pressure of the mixture
Step 2: Calculate the partial pressure of nitrogen
P(N) = mol fraction of N * atmospheric pressure
P(N) = 0.781 * 765.0 torr = 597.5 torr
The partial pressure of nitrogen is 597.5 torr
