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Sophie [7]
3 years ago
9

Carbonic acid (H₂CO₃) is a polyprotic acid. When carbonic acid dissolves in water, which is higher, the concentration of HCO₃- i

ons or the concentration of CO₃²- ions?
Please explain!
Chemistry
1 answer:
Dmitrij [34]3 years ago
7 0

The concentration of CO₃²⁻ ions will be higher

To explain, I want you to imagine H₂CO₃ in water.

we know that it will lose 2 of it's protons, and form 2 ions

The ion which is more stable will have a higher concentration because that ion will refuse to react with anything else, so once something turns into that specific ion, it's not going back... unless there's a more stabler ion possible

In this case, the 2 ions formed are: HCO₃⁻ and CO₃⁽²⁻⁾, drawing the structures of both the ions tells us that both of them have resonance, but the CO₃⁽²⁻⁾ ion has more resonance structures and hence is more stable

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If an ice cube has a mass of 25 grams and it melts, what would the mass of the liquid water be?
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Answer:25grams

Explanation: the mass stays the same even when it changes form

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You have a solution with an unknown concentration of hcl, in order to determine the concentration of hcl you titrate 35.00ml of
slava [35]

Answer:-

0.648 M

Explanation:-

Volume of Ba(OH)2= 34.63ml/1000=0.03463 litre

Number of moles of Ba(OH)2 = 0.3275 M x 0.03463 litre

= 0.01134 moles

Since Ba(OH)2 has 2 OH in its formula,

Number of moles of OH- = 2 x 0.01134=0.02268 moles.

Volume of HCl= 35ml/1000 = 0.035 litre

At the end point number of moles of H+ = number of moles of OH-.

Number of moles of HCL= Concentration of HCl x Volume of HCl

∴ Concentration of HCl = 0.02268 moles/ 0.035 litre

= 0.648 moles/ litre

= 0.648 M

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3 years ago
Hawaii, which sits over a hot spot located near the center of the Pacific
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Shield Volcano . I've been their before

Explanation:

4 0
3 years ago
How many grams of NaOH is needed to neutralize 90 mL of 1.5 N HCl?
AnnZ [28]

mol = conc × v

= 1.5 × 0.09

= 0.135 moles of HCl

HCl + NaOH > NaCl + H2O

1 mole HCl = 1 mole NaOH

0.135 mol HCl = x

x = 0.135 mol NaOH

mass = mol × molar mass

= 0.135 × 40

= 5.4 g

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6 0
3 years ago
Write your question here (Keep it simple and clear to get the best answer) calculate the atomic weight of a metal when 125ml of
lana [24]

Answer:

The answer to your question is 24.32 g

Explanation:

Data

Atomic weight = ?

HCl volume = 125 ml

Molarity = 0.2

mass of metal = 0.304 g

Balanced chemical equation

                       M + 2HCl   ⇒  MCl₂  +  H₂

Process

1.- Calculate the moles of HCl

Molarity = moles / volume (L)

- Solve for moles

  moles = Molarity  x volume

  moles = 0.2 x 0.125

             = 0.025

2.- Calculate the moles of the Metal

                1 mol of M ----------------- 2 moles of HCl

                x                ----------------- 0.025 moles of HCl

                x = (0.025 x 1) / 2

                x = 0.0125 moles of HCl

3.- Calculate the atomic weight of the metal

                atomic weight ---------------- 1 mol

               0.304 g             ---------------0.0125 moles

               Atomic weight = (1 x 0.304) / 0.0125

               Atomic weight = 24.32 g    

             

7 0
3 years ago
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