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il63 [147K]
2 years ago
15

Would you expect the substance to float or sink in water if mass is 25g and volume is 7 cm​

Chemistry
1 answer:
Sonbull [250]2 years ago
4 0

Answer:

Sink

Explanation:

For a substance to float in water, it must be less dense than water. The density of water is 1 g/cm^3. To find the density of the substance, we can do mass/volume, which in this case is 25g/7cm^3. We see that 25/7 > 1, so the substance would sink.

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Identify the medium for the following waves:
Serjik [45]

1. I don't understand what wave exercise waves are?

2. Water is the medium.

3. Air is the medium.

4. The Earth or ground is the medium.

(I think these are right, as the medium is what they are travelling through.)

7 0
3 years ago
Water (2230 g ) is heated until it just begins to boil. If the water absorbs 5.73×105 J of heat in the process, what was the ini
shutvik [7]

Answer: 38.5^0C

Explanation:

To calculate the initial temperature of the water:

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = 5.73\times 10^5J

c = specific heat of water = 4.18J/g^oC

m = mass of water = 2230 g

T_{final} = final temperature of water = 100^0C

T_{initial} = initial temperature of metal = ?

Now put all the given values in the above formula, we get:

5.73\times 10^5J=2230g\times 4.18J/g^oC\times (100-T_i)^0C

(100-T_i)=61.5

T_i=100-61.5)=38.5^0C

Thus, the initial temperature of the water is 38.5^0C

5 0
4 years ago
How many ions are present in 75.0g of magnesium sulfate
Ostrovityanka [42]

Answer:

7.5×10²³ ions

Explanation:

Given data:

Mass of magnesium sulfate = 75.0 g

Number of ions = ?

Solution:

Number of moles of magnesium sulfate:

Number of moles = mass/molar mass

Number of moles = 75.0 g/ 120.36 g/mol

Number of moles = 0.623 mol

Magnesium sulfate formula: MgSO₄

Number of moles of ions in 1 mole of MgSO₄ = 2 mol (Mg²⁺ and SO₄²⁻)

Number of moles of ion in 0.623 moles of MgSO₄:

2 mole ×0.623 = 1.246 mol

Number of ions:

1 mole contain 6.022×10²³ ions

1.246 mol × 6.022×10²³ ions / 1mol

7.5×10²³ ions

4 0
3 years ago
7th grade science can anyone help
Assoli18 [71]
You need to put a question in order for people to answer
4 0
3 years ago
At 400 k, the equilibrium constant for the reaction is kc = 7.0. br2 (g) + cl2 (g) 2brcl (g) a closed vessel at 400 k is charged
jeka57 [31]
a) when Kc = concentration of products / concentration of reactants
  So according  to the reaction equation:
Br2(g) + Cl2(g) → 2BrCl(g)

∴ Kc =[BrCl] ^2 / [Br2][Cl2]

b) when q = [BrCl]^2 / [Br2][Cl2]
and we have [BrCl] = 3 m 
[Br2] = 1 m 
[Cl2] = 1 m
So by substitution:
q= 3^2 / 1*1 = 9 

- and we can see that q > Kc 
the reaction is not at equilibrium that means there are more products and the reaction shifts to the left to increase the reactants and decrease the products to achieve equilibrium.

C) by using ICE table:

              Br2(g) + Cl2(g) → 2BrCl (g)
initial       1               1               3
change  -X              -X            +X
Equ       (1-X)          (1-X)         (3+X)

when Kc = [Brcl]^2/[Cl2][Br2]
by substitution:
7 = (3+X)^2 / (1+X) (1+X)  by solving this equation for X
∴X = 0.215
so at equilibrium:
∴ [Br2] = [Cl2] = 1-0.215 = 0.785 m 
    [BrCl] = 3+0.215 = 3.215 m
4 0
3 years ago
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