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NikAS [45]
2 years ago
11

SCIENTIFIC METHOD

Chemistry
2 answers:
Dominik [7]2 years ago
6 0
Are there any pictures to pair up?
hammer [34]2 years ago
4 0
Smhsmz bomb b V mzvznshx
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Chemical reaction precipitate for Ba (NO3)2+K2 CO3?
Alinara [238K]
Yes, because the net ionic is equation will yield BaCO3 as a precipitate because it is insoluble in water
7 0
3 years ago
Read 2 more answers
Will ya'll help me, please
JulsSmile [24]

Answer:

Either A or D

But i think D

hope this helps =3

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7 0
3 years ago
The formula of water, H2O suggests which of the following?
o-na [289]

Answer: A. There are two hydrogen atoms and one oxygen atom per water molecule.

Explanation:

The chemical formular for water "H2O", means it contain 2 hydrogen atoms and one oxygen atom per molecule.

6 0
3 years ago
Adding/ removing
masya89 [10]

Answer:

False- The number of electrons does not affect the type of element.

Explanation:

The adding/removing of protons is what changes the type of element. for example, if you have a molecule of Boron, which has 5 protons, and you add one proton, you will have created a carbon molecule with 6 protons. The number of protons of an element is its atomic number. Elements can have varying numbers of both electrons and neutrons without changing the type of element.

3 0
3 years ago
When 20.0 g of KI are dissolved in 50.0 mL of distilled water in a calorimeter, the temperature drops from 24.0 °C to 19.0 °C. C
Reil [10]
<h2>Answer:</h2>

<em>8.67kJ/mol</em>

<h2>Explanations</h2>

The formula for calculating the amount of heat absorbed by the water is given as:

\begin{gathered} q=mc\triangle t \\ q=50\times4.18\frac{J}{g^oC}\times(19-24) \\ q=50\times4.18\times(-5) \\ q=-1045Joules \\ q=-1.045kJ \end{gathered}

Determine the moles of KI

\begin{gathered} moles\text{ of KI}=\frac{mass\text{ of KI}}{molar\text{ mass of KI}} \\ moles\text{ of KI}=\frac{20g}{166g\text{/mol}} \\ moles\text{ of KI}=0.1205moles \end{gathered}

Since heat is lost, hence the enthalpy change of the solution will be negative that is:

\begin{gathered} \triangle H=-q \\ \triangle H=-(-1.045kJ) \\ \triangle H=1.045kJ \end{gathered}

Determine the enthalpy of solution in kJ•mol-1

\begin{gathered} \triangle H_{diss}=\frac{1.045kJ}{0.1205mole} \\ \triangle H_{diss}\approx8.67kJmol^{-1} \end{gathered}

Hence the enthalpy of solution in kJ•mol-1 for KI is 8.67kJ/mol

4 0
1 year ago
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