Answer:
Mass of KNO3= 10g
Molar mass of KNO3 = 101.1032g/mol
Volume = 250ml = 0.25L
No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3
no of mole of KNO3 = 10/101.1032
No of mole of KNO3 = 0.09891
molarity of KNO3 = no of mole of KNO3/Vol (L)
Molarity = 0.09891/0.25 = 0.3956M
Molarity of KNO3 = 0.3956M
4.00 moles of sodium has a mass of 91.96 grams.
To find an element's molar mass, you can use its atomic weight.
Answer:
Research is constantly deepening our understanding of chemistry, and leading to new discoveries. Chemistry will help us solve many future problems, including sustainable energy and food production, managing our environment, providing safe drinking water and promoting human and environmental health.Chemistry is a big part of your everyday life. You find chemistry in daily life in foods you eat, air you breathe, soap, your emotions and literally every object you can see or touch. ... Food is made from chemicals. Many of the changes you observe in the world around you are caused by chemical reactions.By observing chemical reactions, we are able to understand and explain how the natural world works. Chemical reactions turn food into fuel for your body, make fireworks explode, cause food to change when it is cooked, make soap remove grime, and much more.
Answer and Explanation:
The options aren't listed in your question, but here are some units that are regularly and normally used (in the classroom and in the outside world):
(The SI unit of distance and displacement is the meter. The SI unit of time is the second.)
<u>Meters per Second (m/s)</u>
kilometers per hour (km/hr)
kilometers per second (km/sec)
To find the average speed, you do distance divided by time.
To find the average velocity, you do the final position minus the initial position, divided by the final time minus the initial time.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
<em><u></u></em>
<em><u>I hope this helps!</u></em>
Answer:
The new temperature is 373 K
Explanation:
Step 1: Data given
Volume air = 5000 mL = 5.0 L
Temperature = 223K
New volume = 8.36 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒V1 = the initial volume = 5.0 L
⇒T1 = the initial temperature = 223 K
⇒V2 = the new volume = 8.36 L
⇒T2 = the new temperature
5.0/223 = 8.36 /T2
T2 = 373 K
The new temperature is 373 K
