Answer:
1 and 4
Explanation:
in both pictures the temperature is cooling down
If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.
<h3>What is entropy? </h3>
The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.
Unit of entropy = J/K
<h3>Formula:</h3>
∆s = ∆Q/T
where,
∆s = change in entropy of the surrounding = -326J/K
∆Q = heat absorbed from surrounding
T = Temperature = 451K
∆Q = ∆s × T
∆Q = -326 × 451
∆Q = 147,026 J
∆Q = 147.026 kJ
Thus we find that the heat absorbed by the system is 147.026 kJ.
learn more about entropy:
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they would be more detailed? what type of cells though?
Answer: (C) Vaporizing
Explanation:
Vaporization is the process in which the substance change the state of of liquid into the gas state.
The vaporization process require the largest input of the energy as when the state is in the solid state then, the solid substances contain the strong forces of the attraction and they require high energy to break these strong bonds.
For changing the liquid state into the gases state we require to overcome the surface tension and require enough energy for acquiring the vaporization state.
Therefore, option (C) is correct.
Answer:
186.9Kelvin
Explanation:
The ideal gas law equation is PV
=
n
R
T
where
P is the pressure of the gas
V is the volume it occupies
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821
atm L
/mol K
T is the absolute temperature of the gas
Ensure units of the volume, pressure, and temperature of the gas correspond to R
( the universal gas constant, equal to 0.0821
atm L
/mol K
)
n
=
3.54moles
P= 1.57
V= 34.6
T=?
PV
=
n
R
T
PV/nR = T
1.57 x 34.6/3.54 x 0.0821
54.322/0.290634= 186.908620464= T
186.9Kelvin ( approximately to 1 decimal place)
