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quester [9]
2 years ago
6

Which of the following is a norm or value that sports may socialize children about

Chemistry
1 answer:
Roman55 [17]2 years ago
7 0
Answer is: <span>B to respect authority .
</span>Sport helps that children learn to respect authority, rules, team colleagues and opponents. Sport also helps children to learn skills that will help them in school, build self-esteem, lower levels of antisocial behaviour in children, <span>develops healthy physical activity and habits.</span>
You might be interested in
If an ion has 26 protons and 24 electrons what is the charge on the ion
Dmitry_Shevchenko [17]

Answer:

give the ion X

<h2>X2+</h2>

Explanation:

it is positively charged because the protons are more than electrons

6 0
2 years ago
In nature, one common strategy to make thermodynamically unfavorable reactions proceed is to couple them chemically to reactions
padilas [110]

Answer:

\triangle G= -6.7 KJ/mol

Explanation:

From the question we are told that:

Chemical Reactions:

X=A⇌B,ΔG= 14.8 kJ/mol

Y=B⇌C,ΔG= -29.7 kJ/mol

Z=C⇌D,ΔG= 8.10 kJ/mol

Since

Hess Law

The law states that the total enthalpy change during the complete course of a chemical reaction is independent of the number of steps taken.

Therefore

Generally the equation for the Reaction is mathematically given by

T = +1 * X +1 * Y +1 *Z

Therefore the free energy, ΔG is

\triangle G=1 * \triangle G*X +1 * \triangle G*Y +1 * \triangle G *Z

\triangle G= +1 * (14.9) +1 * (-29.7) +1 * (8.10)

\triangle G= -6.7 KJ/mol

5 0
2 years ago
In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
How many moles are there in 5.30 x 1024 atoms of silver?
Rus_ich [418]

Answer:

The mass of

4.6

×

10

24

atoms of silver is approximately 820 g.

Explanation:

In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.

1

mole atoms Ag=6.022xx10

23

atoms Ag

Molar mass of Ag =#"107.87 g/mol"#

Multiply the given atoms of silver by

1

mol Ag

6.022

×

23

atoms Ag

. Then multiply times the molar mass of silver.

4.6

×

10

24

atoms Ag

×

1

mol Ag

6.022

×

10

23

atoms Ag

×

107.87

g Ag

1

mol Ag

=

820 g Ag

6 0
2 years ago
How do you balance the equation in number one?
AleksAgata [21]
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O

To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

O- 4              O- 7 (same reason as above) 

Pb- 1            Pb- 1 

Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

2NaNO3

Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

Na- 2             Na- 2 

N- 2              N- 2 (it balanced out) 

O- 7 (coefficient times subscript, plus lone O)  O- 7 (balanced out) 

Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything). 

Now to put it back together, it will look like this: 

2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
3 0
3 years ago
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