Which of the following is a norm or value that sports may socialize children about

1 answer:

7 0

Answer is: B to respect authority .
Sport helps that children learn to respect authority, rules, team colleagues and opponents. Sport also helps children to learn skills that will help them in school, build self-esteem, lower levels of antisocial behaviour in children, develops healthy physical activity and habits.

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When an aqueous solution of silver nitrate is

Andre45 [30]

Answer:

$K^{+}$ and $NO_{3}^{-}$

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

$Ag^{+}$ (aq) + $NO_{3} ^{-}$ (aq) + $K^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s) +

$K^{+}$ and $NO_{3} ^{-}$ do not change, so they are the spectator ions and are removed

The ionic equation is:

$Ag^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s)

8 0

3 years ago

The cis and trans geometric isomers of a compound have different chemical and physical properties. Draw the structure of the geo

frutty [35]

Answer: The structure of the geometrical isomers are attached below.

Explanation:

Cis- and Trans- isomers are the geometrical isomers which have same chemical formula but different structural formula

According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.

If the highest priority groups are on the same side, it is known as cis-form and if the highest priority groups are on opposite side, it is known as trans-form.

We are given a chemical compound, which is 2-pentene.

In this the highest priority groups are methyl and ethyl groups.

When the groups are on the same side, it forms cis-form and when the groups are on the opposite side, it forms trans-form

The structure of the geometrical isomers are attached below.

7 0

3 years ago

A decay series starts with the synthetic isotope ²³⁹₉₂U. The first four steps are emissions of a β⁻ particle, another β⁻, an a p

VladimirAG [237]

Thorium series could start by this sequence.

<h3>Brief explanation</h3>

To write balanced equations for nuclear decay processes. It's important to remember that the mass number and the atomic numbers must be balanced. And so what that means is that if we look at an elements nuclear symbol, the atomic number is the bottom number and the top number, the superscript, is the mass number, and so when we add them up on both sides, they have to be equal. There are two different ways in which decay can occur.

In this, series one is through beta decay, which means that the following particle is produced. The other is Alpha Decay, which produces this particle. Both are products. So if we start off with uranium to 39 you read it in nuclear notation, which means we have to find the atomic number just 92 and it undergoes beta decay.

So that means that it produces this particle find the second particle we used the atomic number, so 92 equals minus one plus x, where X equals 93 which is Neptune IAM. The mass number of our new isotope is zero plus X equals to 39 where X equals to 39. This product becomes the reactant in my next decay, which is also a beta decay. And to find the unknown element we do the same here.

Except for that it's 93 equals minus one plus x, where X is 94 which is P u plutonium, and the mass number is zero plus X equals to 39 or to 39. The next decay starts with the isotope that we just form to 39 p. U. This time it's an Alpha decay. So we produce this particle to find the unknown. Element 94 equals two plus x, where X equals 92 which takes us back to uranium.

Find the mass number of this isotope 2 39 equals four plus X, where X equals to 35. Finally, for the last decay, you have another Alpha decay starting with uranium to 35 making an alpha particle. The atomic number will be 90 which is T H and the top is 2 31 For the mass number. This begins the natural decay, series of thorium .