Answer:
2.0 atm is the difference between the ideal pressure and the real pressure.
Explanation:
If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C
Moles of argon = n = 1.00 mol
Volume of the container,V = 0.500 L
Ideal pressure of the gas = P
Temperature of the gas,T = 27 °C = 300.15 K[/tex]
Using ideal gas equation:


Vander wall's of equation of gases:
The real pressure of the gas= 
For argon:
b=0.03219 L/mol.



Difference :
2.0 atm is the difference between the ideal pressure and the real pressure.
Answer:
Oxidation is defined as the chemical process in which substance loses electron and hydrogen or gain oxygen while in the process of reduction, substance gains electron and hydrogen or loses oxygen.
So, from the given equation:
a. It is an oxidation reaction as Rb loses one elctron.
b. It is a reduction reaction as Te gains two electrons and become Te2-
c. It is a reduction reaction as H atom gains electrons.
d. It is an oxidation reaction as P loses 3 electrons.
They have a complete electronic configuration .their P shell is p6 therefore cannot gain or loose electron.
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