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2 years ago

What is the potential energy in J of a bungee jumper standing on a 0.109 km bridge that weighs 85 kg?

Physics

1 answer:

KatRina [158]2 years ago

4 0

Considering the definition of potential energy, the potential energy of the bungee jumper is 90,889.65 J.

<h3>Potential energy</h3>

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

Ep is the potential energy in joules (J).
m is the mass in kilograms (kg).
h is the height in meters (m).
g is the acceleration of fall in m/s² (approximately 9.81 m/s²).

<h3>Potential energy in this case</h3>

In this case, you know:

m= 85 kg
g= 9.81 m/s²
h= 0.109 km= 109 m (being 1 km= 1000 m)

Replacing in the definition of potential energy:

Ep= 85 kg × 9.81 m/s² × 109 m

Solving:

Finally, the potential energy of the bungee jumper is 90,889.65 J.

Learn more about potential energy:

brainly.com/question/24933254

brainly.com/question/15896499

brainly.com/question/14456667

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Answer:

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2 years ago

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A circuit contains two 1.5 volt battery and a bulb with a resistance of 3 ohms. Calculate the current

horrorfan [7]

Answer:

<em>The current is 1 A</em>

Explanation:

<u>Current in a Series Connection </u>

When two or more elements are connected in series, all of them have the same current, and the sum of their individual voltages is the total voltage applied to the circuit.

According to Ohm's law:

V=R.I

Where V is the voltage, R is the resistance and I is the current of a circuit.

We have a voltage of V=1.5 V + 1.5 V = 3 V and a resistance of R=3 ohms.

We can calculate the current by solving for I:

$\displaystyle I=\frac{V}{R}=\frac{3}{3}=1\ A$

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2 years ago

Air pressure increases as you travel higher above sea level. This is the reason that cabins in commercial airliners require pres

irakobra [83]

The answer is true about the cabins in commercial airliners that require pressurization.

<h3>Why are the cabins of commercial airplanes pressurized?</h3>

Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.

So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.

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1 year ago

Submarine a travels horizontally at 11.0 m/s through ocean water. it emits a sonar signal of frequency f 5 5.27 3 103 hz in the

xeze [42]

Velocity of submarine A is vs = 11.0m/s
frequency emitted by submarine A. F = 55.273 × 10∧3HZ
Velocity of submarine B = vO = 3.00m/s
The given equation is
f' = ((V + vO) ((v - vS)) × f
The observer on submarine detects the frequency f'.
The sign of vO should be positive as the observer of submarine B is moving away from the source of submarine A.
The speed of the sound used in seawater is 1533m/s
The frequency which is detected by submarine B is
fo = fs (V -vO/ v +vs)
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3 years ago

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Leno4ka [110]

Answer:

Anna is correct.

Explanation:

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