Ask question

Ask question

All categories

3 years ago

10

Auroras occur at _____ of a planet. the equator the north magnetic pole only the south magnetic pole only both magnetic poles

1 answer:

goldenfox [79]3 years ago

3 0

<span>
The answer is - both magnetic poles</span>

<span>In the earth's southern magnetic pole, auroras are known as aurora austalis or southern lights while in the northern magnetic pole they are known as aurora borealis or northern lights.</span>

<span>They are caused by charged particles borne in solar winds that are escaping from the sun. As they approach the earth, the winds distort the earth's magnetic field which allows some particles to enter the earth's atmosphere, where they excite the gases and make them glow with spectacular display of colors.</span>

<span>
</span>

<span>
</span>

You might be interested in

So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa

USPshnik [31]

Explanation:

(c) I assume we're looking for mA.

Sum of forces on B in the -y direction:

∑F = ma

mBg − T = mBa

Sum of forces on A in the +x direction:

∑F = ma

T = mAa

Substitute:

mBg − mAa = mBa

mBg − mBa = mAa

mA = mB (g − a) / a

Plug in values:

mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))

mA = 495 kg

The answer key seems to have a mistake. It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.

8 0

3 years ago

Can someone help me plz

yKpoI14uk [10]

The height increases (c)

5 0

3 years ago

How are hypotheses tested?

Mandarinka [93]

Answer:

by making observation hope it's helpful

8 0

2 years ago

Read 2 more answers

The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.3 cm pipes. (a) If the flow rates in the thr

Verdich [7]

Answer:

a)54L/min

b)0.845

Explanation:

a) A x V= $A_1V_1+ A_2V_2+A_3V_3$

where suffix 1,2,3 refers to the three pipes.

=27L/min+16L/min+11 L/min

=54L/min

b) A x V=54L/min => $\frac{\pi }{4} d^2$ x v

d= 2 cm

$\frac{\pi }{4} d^2$ x v = 54

v= $\frac{4}{\pi }$ x $\frac{54}{2^2}$

-> $A_1$ x $V_1$ =27L/min => $\frac{\pi }{4} d_1^2$ x $v_1$

$d_1$ = 1.3cm

$\frac{\pi }{4} d^2$ x $v_1$ = 27

$v_1$ = $\frac{4}{\pi }$ x $\frac{27}{1.3^2}$

Next is to find the ratio of speed i.e $\frac{v}{v_1}$

$\frac{4}{\pi }$ x $\frac{54}{2^2}$ / $\frac{4}{\pi }$ x $\frac{27}{1.3^2}$ => $\frac{54}{27}$ $\frac{1.3^2}{2^2}$

$\frac{v}{v_1}$ = 0.845

8 0

2 years ago

What is the farthest planet from earth?

IRINA_888 [86]

The answer is pluto. just look it up

7 0

3 years ago