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jarptica [38.1K]
3 years ago
5

Agatha has 1kg samples of two substance- A and B. Substance A has a higher specific heat capacity than substance B. Both samples

cool down by 10C. Which will release more heat - A or B
Physics
1 answer:
Sav [38]3 years ago
7 0

Answer:

Substance A will release more heat.

Explanation:

Let suppose that both substances experiment an entirely sensible heat process and are incompressible and begin at the same temperature. Physically speaking, specific heat (c), measured in kilojoules per kilogram-degree Celsius, can be described by following expression:  

c = \frac{Q}{m\cdot (T_{f}-T_{o})} (1)

Where:

Q - Released heat, measured in kilojoules.

m - Sample mass, measured in kilograms.

T_{o}, T_{f} - Initial and final temperatures of the sample, measured in degrees Celsius.

If we know that c_{A}> c_{B}, m_{A} = m_{B}, T_{A,o} = T_{B,o} and T_{A,f} = T_{B,f}, then we have the following inequation:

\frac{Q_{A}}{m\cdot (T_{A,f}-T_{A,o})} > \frac{Q_{B}}{m\cdot (T_{B,f}-T_{B,o})}

Q_{A} > Q_{B}

Substance A will release more heat.

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Explanation:

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A 1.0 kg football is given an initial velocity at ground level of 20.0 m/s [37° above horizontal]. It gets blocked just after re
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1) Data:

Vo = 20 m/s
α = 37°
Yo = 0
Y = 3m

2) Questions: V at Y = 3m and X at Y = 3 m

3) Calculate components of the initial velocity

Vox = Vo * cos(37°) = 15.97 m/s

Voy = Vo * sin(37°) = 12.04 m/s

4) Formulas

Vx = constant = 15.97 m/s

X = Vx * t

Vy = Voy - g*t

Y = Yo + Voy * t - g (t^2) / 2

5) Calculate t when Y = 3m (first time)

Use g ≈ 9.8 m/s^2

3 = 12.04 * t - 4.9 t^2

=> 4.9 t^2 - 12.04t + 3 = 0

Use the quadratic equation to solve the equation

=> t = 0.28 s and t = 2.18s

First time => t = 0.28 s.

6) Calculate Vy when t = 0.28 s

Vy = 12.04 m/s  - 9.8 * 0.28s = 9.3 m/s

7) Calculate V:

V = √ [ (Vx)^2 + (Vy)^2 ] = √[ (15.97m/s)^2 + (9.30 m/s)^2 ] = 18.48 m/s

tan(β) = Vy/Vx = 9.30 / 15.97 ≈ 0.582 => β ≈ arctan(0.582) ≈ 30°

Answer: V ≈ 18.5 m/s, with angle ≈ 30°

8) Calculate X at t = 0.28s

X = Vx * t = 15.97 m/s * 0.28s = 4,47m ≈ 4,5m

Answer: X ≈ 4,5 m
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