Factor the numerator and denominator and cancel the common factors.
The answer would be 1/4
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Step-by-step explanation:
Area of circle = πr², π = 22/7 or 355/133. Here it is said to use '3.14'. I will use the same.
Volume = cross-section area * height
Cross-section area of bigger one = π(3m)²
Volume = π(3m)² * height
= 9π * 5 m³ = 45π m³
Cross-section area of smaller one= π(1m)²
Volume = π(1m)² * height
= π * 5 m³ = 5π m³
Since a large part(cylinder of 1 m is not here):
Required volume = total volume - volume of smaller circle(cylinder)
= 45π - 5π m³
= 40π m³ = 40(3.14) m³
= 125.6 m³
Answer: The shorter piece of the pipe is 9.25 inches long
Step-by-step explanation: First, we need to make an equation. 50 = 13 + 4x + x. We do subtraction first so it becomes 37 = 4x. Divide both sides by 4 so x = 9.25. The short piece of the pipe is 9.25 inches. Hope this helps!
Answer: bro I'm sorry I don't know how to help you please give me points
Step-by-step explanation:
Don't know how to help you sorry
