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vaieri [72.5K]
1 year ago
8

Perform the following operation

Chemistry
1 answer:
Paul [167]1 year ago
4 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:2.8 × {10}^{-5}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \dfrac{2.36 \times 10 {}^{ - 2} }{8.4  \times {10}^{2} }

\qquad \tt \rightarrow \:  \dfrac{2.36  }{8.4   } \times  \cfrac{10 {}^{ - 2} }{10 {}^{2} }

\qquad \tt \rightarrow \:  0.28 \times 10 {}^{ - 2 - 2}

\qquad \tt \rightarrow \:  0.28  \times 10 {}^{  - 4}

\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Explanation:

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7 0
3 years ago
4HCl(g)+O2(g)⟶2Cl2(g)+2H2O(g) Calculate the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2. mass:
FromTheMoon [43]

The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Moles of hydrochloric acid = 0.385 mol

Mass of chlorine gas =?

Chemical equation:

4HCl +  O₂ → 2Cl₂  + 2H₂O

Now we will compare the moles of Cl₂ with HCl.

                 HCl           :               Cl₂

                   4             :               2

                0.385       :              2÷4× 0.385 = 0.1925 mol

Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.1925 mol × 71 g/mol

Mass of Cl₂ =  13.6675 g

Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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2 years ago
How many elements and atoms are in marble
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7 0
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I NEED HELP ASAP!!!
Rus_ich [418]

Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

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T

is temperature in Kelvin.

The question already gives us the values for

p

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