To be honest, I learned this in school so I'll tell you XD
The formula of sodium oxide is Na2O
Answer:
uh yeah I think so technically
Answer:
Explanation:
That's correct. Once Aluminum becomes an ion, it is very hard to force it to take back its electrons. Only a few elements can do it. Iron is not one of them.
Answer:
N - 1s²2s²2p³
Explanation:
Nitrogen is located in the p-block of the periodic table (groups 13-18) and is on the 2nd period.
The 2nd period tells us the principal energy level (a quantum number) is n = 2. Therefore, it must have already filled up the 1s sublevel.
The groups 13-18 on period 2 tells us that the 2s sublevel is also filled.
Nitrogen is located in Group 15. That means that there are 3 electrons that have filled the 2p sublevel, out of a possible 6.
Therefore, our electron configuration is 1s²2s²2p³
2p³ (Shorthand Config)
[He] 2s²2p³ (Noble Gas Config)
Answer:

Explanation:
Hello,
In this case, for the given reaction:

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

Best regards.