9) Which statement about a ray is true?

Can someone give me the answer for this? thanks!!

vlabodo [156]

Answer:

Step-by-step explanation:

No

3 0

3 years ago

What is the value of q in the equation 5q-10=75

Alex

Answer:

q=17

Step-by-step explanation:

5q-10=75

add 10 to both sides to cancel out -10 on the left side

5q-10+10=75+10

5q=85

divide both sides by 5 to get rid of the 5 in 5q

5q/5=85/5

resulting in:

q=17

5 0

2 years ago

Find the volume of a prism whose area of base is 44cmsquare and height is22cm

vovangra [49]

For this problem, you can use the volume of a prism equation:
V=Bh
Where B is the area of the base and h is the height.

So to solve this problem, all you have to do is mutiply 44 square cm by 22 cm.
44 square cm • 22 cm = 968 cubic cm

4 0

2 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

Ayana works at Eastern Community College as a math teacher. She will

AveGali [126]

Answer:

a. $2622.00

Step-by-step explanation:

After taking out federal health insurance taxes, Ayana's pay for the year will be ...

$45000 × (1 - 0.224) = $45000 × 0.776 = $34,920

On a monthly basis, that is ...

$34,920/12 months = $2910 per month

Then, additional deductions of $3 + 85 + 200 = $288 are made, so her pay will be ...

$2910 -288 = $2622 per month

_____

<em>Comment on federal taxes</em>

Federal income taxes are not accounted for in the problem statement. If Ayana can claim "head of household" status (and is not married), she will have federal income tax on the order of $121 per month deducted from the above amount, assuming her retirement plan deduction is "before tax."

8 0

3 years ago