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adoni [48]
3 years ago
9

Convert 65 miles per hour to kilometers per hour. Use unit analysis to set up and solve.

Mathematics
2 answers:
denpristay [2]3 years ago
6 0
Since there's 1.60934 kilometers in a mile, we just have to multiply to make the conversion:
65mi * 1.60934 = 104.607 km
Artist 52 [7]3 years ago
3 0

Answer:

104.607 Kilometers per Hour.

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A number k less than 10
svlad2 [7]
Your answer would be

10 - k
5 0
4 years ago
Ninety two and forty on hundredths in standard decimal form
makkiz [27]

Answer:

92.40 is the answer for your question.

3 0
3 years ago
For each equation, determine whether it represents a direct variation, an inverse variation, or neither.
SSSSS [86.1K]

we know that in direct variation as x increase y also increases.

in indirect variation x decreases y increase and vice versa.

in part a we have x at top (numerator ) and y at denominator it mean indirect variation (as x increases y decreases).

to find k we know that for indirect variation xy=k

if we rewrite the equation x=9/y we get xy=9

which mean k=9 .

in part b we have 4xy=20 if we simplify this equation we get

xy=20/4=5

so here if we rewrite in terms of x.

we get x=5/y which represents indirect variation.

and we know xy=k

we have xy=5 .so k=5

8 0
3 years ago
Write the following number in standard form. three and fifteen hundredths 3.15 3.015 315 3.105
soldier1979 [14.2K]
3.105 I believe.. not 100% sure.
3 0
3 years ago
Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of
GaryK [48]

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is KE=\frac{1}{2}mv^2

Where

KE is the kinetic energy

m is the mass

v is the velocity

  • Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
  • Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

\frac{1}{2}mv^2

<u />

<u>KE of 2nd mass is:</u>

\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4

Hence, the kinetic energy of the 2nd mass is 4 times the first.

6 0
3 years ago
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