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Rashid [163]
3 years ago
8

Which of the following equations violates the law of conservation of mass?

Chemistry
2 answers:
Sonja [21]3 years ago
5 0

Answer: Option (D) is the correct answer.

Explanation:

Law of conservation of mass states that energy can neither be created nor it can be destroyed. It can only be transformed from one form to another.

Therefore, in a chemical reaction an equation can only be balanced if the number of reactants equal the number of products because energy required for reactants is utilized in the formation of the products.

For example, 2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2} is a balanced equation because the number of reactant atoms equal the number of product atoms.

Thus, we can conclude that out of the given options, 3Ca + 2Cr(NO3)_3 \rightarrow 3Ca(NO3)_{3} + 2Cr equations violates the law of conservation of mass because number of reactant atoms does not equal the number of product atoms.

sammy [17]3 years ago
3 0
D is the answer.
On the left, there are 3 atoms of Ca, 2 atoms of Cr, 6 atoms of N, and 18 atoms of O.
On the right, there are 3 atoms of Ca, 9 atoms of N, 27 atoms of O, and 2 atoms of Cr.
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At which temperature is water in its gas phase (water vapor)?
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Which of the following example(s) from everyday life are made possible by modern chemistry?
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If 175 g of phosphoric acid reacts with 150.0 g of sodium hydroxide, what is the limiting reactant? How many grams of sodium pho
Evgen [1.6K]

Answer:

NaOH is the limiting reactant.

204.9 g of sodium phosphate are formed.

51.94 g of excess reactant will remain.

Explanation:

The reaction that takes place is:

  • H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

First we <u>convert the mass of both reactants to moles</u>, using their <em>respective molar masses</em>:

  • H₃PO₄ ⇒ 175 g ÷ 98 g/mol = 1.78 mol
  • NaOH ⇒ 150 g ÷ 40 g/mol = 3.75 mol

1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.

--

We <u>calculate the produced moles of Na₃PO₄</u> using the <em>limiting reactant</em>:

  • 3.75 mol NaOH * \frac{1molNa_3PO_4}{3molNaOH} = 1.25 mol Na₃PO₄

Then we <u>convert moles into grams</u>:

  • 1.25 mol Na₃PO₄ * 163.94 g/mol = 204.9 g

--

We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:

  • 3.75 mol NaOH * \frac{1molH_3PO_4}{3molNaOH} = 1.25 mol H₃PO₄

We substract that amount from the original amount:

  • 1.78 - 1.25 = 0.53 mol H₃PO₄

Finally we <u>convert those remaining moles to grams</u>:

  • 0.53 mol H₃PO₄ * 98 g/mol = 51.94 g
3 0
3 years ago
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