Answer:
Obtain the conversion factor by dividing the required yield (from Step 2) by the old yield (from Step 1). That is, conversion factor = (required yield)/(recipe yield) or conversion factor = what you NEED ÷ what you HAVE.
Explanation:
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial pressure (P1) = 1atm
Initial temperature (T1) = 0°C = 0°C + 273 = 273K
Final temperature (T2) = 280°C = 280°C + 273 = 553K
Final pressure (P2) =...?
Step 2:
Determination of the new pressure of the gas.
Since the volume of the gas is constant, the following equation:
P1/T1 = P2/T2
will be used to obtain the pressure. This is illustrated below:
P1/T1 = P2/T2
1/273 = P2 / 553
Cross multiply
273x P2 = 553
Divide both side by 273
P2 = 553/273
P2 = 2.03atm
Therefore, the new pressure of the gas will be 2.03atm
Molar mass MgCO3 => 84.31 g/mol
1 mole MgCO3 ----------- 84.31 g
1.5 moles MgCO3-------- ??
1.5 x 84.31 / 1 => 126.465 g
Answer: E=∆H*n= -40.6kj
Explanation:
V(CO) =15L=0.015M³
P=11200Pa
T=85C=358.15K
PV=nRT
n=(112000×0.015)/(8.314×358.15)
n(Co)= 0.564mol
V(Co)= 18.5L = 0.0185m³
P=744torr=98191.84Pa
T= 75C = 388.15k
PV=nRT
n= (99191.84×0.0185)/(8.314×348.15)
n(H2) = 0.634mol
n(CH30H) =1/2n(H2)=1/2×0.634mol
=0.317mol
∆H =∆Hf{CH3OH}-∆Hf(Co)
∆H=-238.6-(-110.5)
∆H = 128.1kj
E=∆H×n=-40.6kj.
robert hooke and his microscopeExplanation:
