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Lady bird [3.3K]
3 years ago
8

What happens after excitation in spectroscopy.​

Chemistry
1 answer:
Bess [88]3 years ago
4 0

Answer:

When a molecule is excited to a higher state it often ends up in its lowest excited state S1 and then emits radiation.

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Determine the density of gold if a 475.09g sample occupy a space of 24.6cm^3
Ira Lisetskai [31]

Answer:

The answer is

<h2>19.31 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of gold = 475.09g

volume = 24.6 cm³

The density of the gold is

density =  \frac{475.09}{24 .6}  \\  = 19.3126016...

We have the final answer as

<h3>19.31 g/cm³</h3>

Hope this helps you

6 0
3 years ago
A civil engineer designs mostly:
Ilia_Sergeevich [38]
I’m pretty sure that they mostly design building structures!
6 0
3 years ago
A group of the periodic table is called
nadezda [96]

Answer:

The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups.

Explanation:

6 0
3 years ago
Read 2 more answers
The specific heat of a certain type of metal is 0.128J/(g.°C). What is the final temperature if 305 J of hear is added to 28.8 g
klasskru [66]

Answer: Temperature final = 103 °C

Explanation: To solve for final temperature we use the equation of heat:

Q= mc∆T

Next derive the equation to find final temperature

Q = mc(T final - T initial)

Q / mc = T final - T initial

Transpose T initial and change the sign so that T final will be left.

T final = Q / mc + T initial

Substitute the values:

T final = 305 J / 28.8 g x 0.128 J/(g°C)

= 305 J / 3.6864 J/°C

= 82.7 + 20.0°C

= 103 °C final temperature.

8 0
3 years ago
Chemistry! Help! Please!
Ratling [72]

Question 1

The correct answer is a.

Explanation

The relationship between pH and pOH is given by

pH + pOH = 14, We can use pH=-log[H^+] and pOH= -log[OH^-]. In a we are given the concentration of [OH] and so we use that to find the pOH, then from pOH we can find the pH.

pOH= -log [2.4 \times 10^-^2] = 1.62\\\\pH = 14 - 1.62= 12.38

b.pH=-log(1.53 \times 10^-^2) = 1.82

c. HCl is a strong acid so it dissociates to 0.0001 H^+ and 0.0001 Cl^-, hence

pH= -log[0.0001] = 4

d.pOH= -log [4.4 \times 10^-9] = 8.36\\\\pH= 14- 8.36 = 5.64

a.[OH^-] = 2.4 \times 10^-^2 has a pH 12.36 which is greater than 7

Question 2

The correct answer is d O_2(g).

Explanation

This is because solids and liquids do not appear in the equilibrium constant expression. Since K= \frac{[products]}{[reactants]}.

For the equation

2PbS_(_s_) + 3O_2_(_g_) + C_(_s_) \implies 2Pb _(_s_) + CO_2_(_g_) + SO_2(_g_)

K= \frac{[CO_2][SO_2]}{[O_2]}

Question 3

The correct answer is c

In a molecule the oxidation number are assigned to get the sum of a neutral charge or ion. The overall charge of SO_4^2^- is -2 and in all its compounds oxygen has -2 charge, hence

S+ 4O = -2\\S+4(-2)=-2\\\implies S= -2 +8 = +6

Question 4

The correct answer is b. An oxidising agent must gain electrons in a reaction, thus it is the one that undergoes reduction.In order find out what is being reduced we write half reactions for molecules that change their state. Ag^+ and K^+ are spectactor ions in this reaction.

Cl_2 + 2e \implies 2Cl^-\\\\NO_2 +H_2O \implies NO_3 +2H^+ +2e\\\\H^+ + OH^- \implies H_2O\\

In the chloride half reaction Cl_2 gains electrons to become Cl^- ions.

Question 5

The last element D is correct. When a nucleus decays by beta emission it produces a daughter nucleus that has same mass number but different atomic number. Therefore beta-decay will have equation

\frac{187}{75} Re \implies \frac{187}{76} Os + \beta

Question 6

The correct answer is a. A beta particle is an electron because it has a charge of -1 and has same mass as an electron, while a positron is  a particle with the same mass as an electron  but with a positive charge.

4 0
3 years ago
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