4.42 g mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane.
It's easy to find the molecular mass of a compound with these steps: Determine the molecular formula of the molecule. Use the periodic table to determine the atomic mass of each element in the molecule. Multiply each element's atomic mass by the number of atoms of that element in the molecule.
The molar mass of any compound can be found out by adding the relative atomic masses of each element present in that particular compound.
Hexane is an organic compound, a straight-chain alkane with six carbon atoms and has the molecular formula C₆H₁₄.
Therefore,
⇒ 0.115 g of Hexane x (0.25 mol CCl4/1 mol hexane) x (153.81 g of CCl4/1 mol CCl4) = 4.42g CCl4.
To learn more about CCL4 and Hexane here
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6 Li + N2 = 2 Li3N
6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------> ?
moles Li3N = 0.24 * 2 / 6
= 0.48 / 6
= 0.08 moles of li3N
hope this helps!.
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
= 25/1000 liter
= 0.025 liter
V2 = 18 ml
= 18/1000 liter
= 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
= (1 * 0.018)/0.025
= 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
Then why did you ask ??...........
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I would start by converting g/mL to g/L
75.00g/1000.0mL = 75.00g/L
Stoichiometrically, flip 75 onto the bottom so that grams cancel out and we are left with the number of L required.
(L/75.00g)(15g) -> this is essentially dividing 15g by 75g, which cancels the unit g, leaving us with 0.2L. If the question requires an answer in mL, just multiple the number of L by 1000.
The patient requires 200mL of glucose solution to receive his 15g of glucose.
