Answer:
Lead to Sulfur = 2 : 1
Explanation:
Given
Represent lead with L and Sulfur with S
L1 = 6.46g for S1 = 1 g
L2= 3.23g for S2 = 1 g
Required
Determine the simple whole number ratio of L to S
Divide L1 by L2
L = L1/L2
L = 6.46g/3.23g
L = 2
Divide S1 by S2
S = 1g/1g
S = 1
Represent L and S as a ratio:
L : S = 2 : 1
Hence, the required ratio of Lead to Sulfur is 2 to 1
819 ml is the volume the gas will occupy at 30.0°C.
Explanation:
Data given:
initial volume of the gas V1 = 590 ml
initial temperature of the gas T1 = -55 degrees OR 218.15
final volume of the gas V2 = ?
final temperature of the gas T2 = 30 degrees OR 303.15
Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.
= 
V2 = 
V2 = 
V2 = 819 ml
The final volume of the gas would be 819 ml.
The longest hydrocarbon chain in the given compound is hexane, therefore it is the parent chain to be considered with one methyl group attached to the 3rd carbon and one chloro attached on the 2nd carbon, therefore the name of the compound is 2-chloro-3-methylhexane
1/8 got it from Yahoo answers and the answer was highlighted with 4 likes.... so most likely thats it