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4 years ago

If a solution has virtually no hydrogen ions what type of ph does it have?

Chemistry

2 answers:

lora16 [44]4 years ago

7 0

D. It has almost no hydrogen ions, therefore it is very basic.

lesya [120]4 years ago

3 0

D. It has no hydrogen ions

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Natural gas burns in air to form carbon dioxide and water, releasing heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔHrxn = -802.3 kJ.

Olenka [21]

Answer:

1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

Explanation:

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g) ,\Delta H_{rxn} =-802.3 kJ$

1) Minimum mass of methane required to raise the temperature of water by 21.0°C.

Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

$Q=mc\Delta T= 45.0 g\times 4.18 J/g^oC\times 21.0^oC$

Q = 3,950.1 J = 3.9501 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 3.950.1 kJ of heat will be given by:

$=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol$

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

$Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC$

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

$=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol$

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

6 0

4 years ago

An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iro

Liula [17]

Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)

4 0

4 years ago

How many moles of water vapor are in 44.8 L of water vapor (H2O) at STP

Damm [24]

Answer:

n = 2 mol

Explanation:

Given data:

Number of moles of water vapors = ?

Volume of water vapors = 44.8 L

Temperature = 273 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

by putting values,

1 atm × 44.8 L = n×0.0821 atm.L/ mol.K × 273 K

44.8 L. atm = n×22.4 atm.L/ mol

n = 44.8 L. atm /22.4 atm.L/ mol

n = 2 mol

3 0

3 years ago

Biochemical reactions in your cells occur best at approximately which temperature

VARVARA [1.3K]

Answer: 98.6˚F

Explanation:

3 0

3 years ago

A website promoting the use of alternative energy vehicles and hybrid technologies claims that "A typical automobile in the USA

svetlana [45]

Answer:

The statement is correct since 500 gallon of gasolin produces 4.56 ton of carbon dioxide.

Explanation:

The combustion of gasoline follows the reation bellow:

C₈H₁₈ (l) + 17,5O₂ (g) → 8CO₂ (g) + 9H₂O (g)

This means that each mol of octane produces 8 mol of CO₂.

1 gallon ______ 4546.09 mL C₈H₁₈

500 gallon ____ x

x = 2,273,045.00 mL C₈H₁₈

1 mL gasoline ______________ 0.703 g

2,273,045.00 mL C₈H₁₈ ____ y

y = 1,597,950.635 g C₈H₁₈

1 mol C₈H₁₈ _____ 126.239 g

y _____ 1,597,950.635 g

y = 12,966.274 mol C₈H₁₈

1 mol C₈H₁₈ ___________ 8 mol CO₂

12,966.274 mol C₈H₁₈ ____ w

w = 103,730.192 mol CO₂

1 mol CO₂ ______________ 44 g

103,730.192 mol CO₂______ z

z = 4564128.448 g CO₂

500 gallon of gasolin produces 4.56 ton of carbon dioxide.

4 0

3 years ago