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4 years ago

What is 1/50 as a decimal number

Mathematics

2 answers:

atroni [7]4 years ago

7 0

To help us get an accurate decimal, we would like a denominator of 100:
1/50 * 2 = 2/100
2/100 = 0.02

Hope this helps!

Julli [10]4 years ago

5 0

.02 is 1/50 as a decimal

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The next term in 3, 12, 48, 192,768,...

geniusboy [140]

3 * 4 = 12

12 * 4 = 48

48 * 4 = 192

192 * 4 = 768

The next number in the sequence is the previous number multiplied by 4:

The next number would be 768 x 4 = 3072

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4 years ago

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OverLord2011 [107]

Answer:

the answer is the second one (6, 9)

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3 years ago

Order these numbers from least to greatest. 0, 1 ,1/2 ,8/9 ,49/100 ,11/20 ,1/13<br><br> pls help.

Troyanec [42]

Answer:

0,1/13,49/100,1/2,11/20,8/9,1

Step-by-step explanation:

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3 years ago

Ryan mows lawns in the summer. He charges $15 for every 1/2 hour of mowing. This is represented by the equation y = 15x, where y

AleksandrR [38]

Answer:

$45 more

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3 years ago

Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe

DerKrebs [107]

Answer:

Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

$2x + y = 60$ i.e. $y=60-2x$

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = $x \times y$

i.e. Area of the rectangular plot = $x\times (60-2x)$

i.e. Area of the rectangular plot = $-2x^2+60x$

<em>Since, the maximum of the quadratic equation $ax^2+bx+c$ will be obtained at $x= \frac{-b}{2a}$ .</em>

Then, the maximum of the area of the plot is at the point $x= \frac{-60}{2\times (-2)}$ i.e. x= 15

Then, maximum area of the rectangular plot = $-2x^2+60x$

i.e. maximum area of the rectangular plot = $-2\times 15^2+60\times 15$

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then, $y=60-2\times 15$ implies $y=60-30$ i.e. y= 30.

Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.

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3 years ago