Answer:
2 m/s².
Explanation:
The forces acting on the crate have been shown in the figure below.
Net force acting on the crate in the horizontal direction = 400 - 250 = 150 N towards right.
For the forces of vertical direction we can write,
Normal force = 150 + Mg = 150 + 250 = 400 N (here g = 10 m/s² have been taken)
The magnitude of frictional force that will act on the crate = μ × Normal force
So, Frictional force = 0.25 × 400 = 100 N
Thus, the net force that will cause acceleration in the crate will be
Force in the right direction - frictional force
= 150 - 100 = 50 N
As we know,
Acceleration =
=
= 2 m/s²
So, the net acceleration in the crate will be 2 m/s².
Given:
An ideal gas expands at constant pressure:
P = 105 pascals
V1 = 1 m3
V2 = 4 m3
then, the gas is compressed to 1/3 of the pressure and volume 2.50 m3.
Work at constant pressure:
W = PΔV
W = 105 pascals * (4 m3 - 1 m3)
W = 315 Joules
Work at constant volume is zero.
The Third Law of Thermodynamics is concerned with the limiting behavior of systems as the temperature approaches absolute zero.
Answer
Anaerobic and aerobic describes that type of physical activity that includes both cardio and strength-training exercises
Explanation:
Given that,
Depth of seawater, h = 11,033 m
Density seawater, p (rho) = 1025 kg/m³
Gauge Pressure , P = ??
Since, we know that:
Pressure, P = pgh
Pressure = 1025 * 9.81 * 11033
Pressure = 1109395723.3 N/m²
or
Pressure = 1.1 x 10∧8 Pascal