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Alexus [3.1K]
3 years ago
13

A plastic rod that has been charged to -21 nc touches a metal sphere. afterward, the rod's charge is -8 nc. (a) what kind of cha

rged particle was transferred between the rod and the sphere, and in which direction? that is, did it move from the rod to the sphere or from the sphere to the rod?
Physics
1 answer:
otez555 [7]3 years ago
3 0
The rod transferred negatively charged particle to the metal sphere. The rod becomes less negatively charged than it was originally (originally it was charged to -21 nc, now it has -8, and -8>-21), so it must have moved 13 nc of negative charge to the sphere. 
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Explanation: In order to solve this problem we have to used the second Newton law given by:

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F-f=m*a where f is the friction force (uk*Normal), from this we have

F= m*a+f=5 Kg*2 m/s^2+0.5*5Kg*9.8 m/s^2= 34.5 N

then f=uk*N=0.5*5Kg*9.8 m/s^2= 24.5N

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3 years ago
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Explanation:

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Let's replace

      ρ = A / (4/3 π R₀³)

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b)

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The area of ​​a sphere is

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Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

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In this case it does not say that the nucleon number is A (F = A), the relationship is

     ρ/ρ2 = 3 / R₀

I see that the two densities are different

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3 years ago
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Answer:

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Explanation:

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A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.727 g, q = 2.73 µC is locat
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