Answer
The second rock will land 2.4s after the first rock
Explanation:
Given that
Height of the building s=50m
We assume that the first rock is acting with gravity so that a=9.81m/s
And initial velocity u=0
Applying the equation of motion
S=ut+1/2at²
50=0*t+1/2(9.81)t²
50=4.905t²
t²=50/4.905
t²=10.19
t=√10.19
t=3.19sec
For the second rock initial velocity u=8m/s and v=0 and a=9.81
Applying the equation of motion
v=u+at
0=8+9.81t
t=-8/9.81
t=0.81sec
Hence the second rock will land 2.4s after the first rock
I.e
3.19-0.81
Just so you know people aren’t replying because the bar graph isn’t show :/
As per the equation: P(momentum)= (mass x velocity) The answer is 680 kg*m/s.
Answer:
9 N
Explanation: Given that L = side of the cube = 10cm = 0.1m
Mass = Density * Volume
Let’s determine the volume of the cube in m^3.
V = L^3
V = 0.1^3 = 0.001m^3
Mass = 0.001 * 2.053 * 10^4 = 20.53kg
Weight = 20.53 * 9.8 = 201.194
Buoyant force = 201.194 – 192 = 9.194 N
This is approximately 9 N.
Answer:
the type of wave
Explanation:
Description: Doppler Effect works on both light and sound objects. For instance, when a sound object moves towards you, the frequency of the sound waves increases, leading to a higher pitch. Conversely, if it moves away from you, the frequency of the sound waves decreases and the pitch comes down.