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SVEN [57.7K]
3 years ago
11

What is the goal of a proof by contradiction?

Mathematics
2 answers:
Aleksandr [31]3 years ago
7 0

Answer: C

Step-by-step explanation: Your statement is wrong and you continue to answer it until you the result is a contradiction.

kifflom [539]3 years ago
6 0

Answer:

B. The contradiction of the statement is proven false, so the original

statement is therefore proven true.

Step-by-step explanation:

We assume the opposite and then get to a point where we get a false statement.   That proves that the the opposite of the opposite ( what we originally wanted to prove) is true.

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I'm testing something, so you can just take the points if you want I don't care.
SVEN [57.7K]

Answer:

...Okay thank you!

Step-by-step explanation:

...... :)

3 0
3 years ago
Read 2 more answers
Please help me asap
Darya [45]
L = rc 
= 26.9 * 9*3.14 / 5
 =  152.04 to nearest 1/100

8 0
3 years ago
Along which axis is the dependent variable traditionally plotted?
Dvinal [7]
The y axis for dependent variables and x axis for independent
7 0
3 years ago
Lines g,h and l are parallel and m&lt; 2 = 129<br> What is the m &lt; L
Bingel [31]
180-129= 51
angle 4 is equal to angle 12 so missing angle 12= 51°
6 0
3 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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