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andre [41]
2 years ago
8

Suzanne deposited x dollars to her savings account. Her old balance was $348.50, and her new balance is $532.20. Find the deposi

ted amount.
Mathematics
2 answers:
Tom [10]2 years ago
8 0

Hello!

Subtract the old balance from new balance to find deposit amount.

⇒ Deposit = $532.20 - $348.50

⇒ Deposit = $183.70

IgorLugansk [536]2 years ago
4 0

Answer:

$183.7

Step-by-step explanation:

To find the deposited amount you need to....

$532.20-$348.50=$183.70

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If a cylinder has a height of 21 cm and a volume of 11,144 cm^3.
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\bf \textit{volume of a cylinder}\\\\
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h=21\\
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Mariulka [41]

Given:

The equation is,

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\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

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\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

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For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

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\begin{gathered} x-3=0 \\ x=3 \end{gathered}

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\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

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