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xenn [34]
2 years ago
7

the accompanying diagram depict's alex's demand for shoes. a. if shoes cost $50 a pair, how many pairs of shoes will alex buy?

Business
1 answer:
luda_lava [24]2 years ago
6 0

If shoes cost $50 a pair, the number of shoes she would buy is 5.

<h3>How many shoes will she buy?</h3>

The image shown is a demand curve. A demand curve shows the relationship between price and quantity demanded. Price is on the y-axis and quantity demanded is on the x-axis.

In order to determine the quantity demanded, trace $50 to the curve and trace it down to the x axis.

Please find attached the diagram used in answering this question. To learn more about the demand curve, please check: brainly.com/question/25140811

#SPJ11

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I live in Indiana all I did was go to the court house and filled they ask you a lot of questions about times and dates and any witness. It was free.
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The Federal Trade Commission (FTC) is a government agency that issues rules, orders, and decisions. The Georgia state legislatur
fomenos

Answer:

c)

Explanation:

Administrative law is the body of law that controls all of the activities as well as the administrative agencies of a specific government. Administrative law includes the rules, orders, and decisions of the Federal Trade Commission. This branch of public law can also enforce certain regulatory agenda that has already been made.

4 0
3 years ago
Nu Company reported the following pretax data for its first year of operations. Net sales 2,910 Cost of goods available for sale
kozerog [31]

Answer:

$434

Explanation:

Net sales                     = $2,910

-Cost of goods sold    = $1,560 (Working)

=Gross profit                = $1350

-Operating expenses  = $730

=Profit before Tax        = $620

-Tax 30%                      = $186

=Net Profit/Net Income= $434

<u>Working</u>

Cost of goods sold = Cost of goods available for sale - Closing Inventory if LIFO is elected

Cost of goods sold = 2,430 - 870 = 1560

5 0
3 years ago
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A travel agent wants to determine how much the average client is willing to pay for a weekend at an all-expense paid resort. The
-Dominant- [34]

Answer:

n=(\frac{1.960(840)}{150})^2 =120.47 \approx 121

So the answer for this case would be n=12 rounded up to the next integer

Explanation:

\bar X=2500 represent the sample mean

\mu population mean (variable of interest)

s=840 represent the sample standard deviation

n represent the sample size  

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =150 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval, the significance level if 5% and the critical value would be z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(840)}{150})^2 =120.47 \approx 121

So the answer for this case would be n=12 rounded up to the next integer

8 0
3 years ago
When interest is compounded continuously, the amount of money increases at a rate proportional to the amount S present at time t
liubo4ka [24]

Answer:

a) - r=5%: S=$ 5,136.10

- r=4%: S=$ 4,885.61

- r=3%: S=$ 4,647.34

b) - r=5%: t=14 years

- r=4%: t=17 years  [/tex]

- r=3%: t=23 years  [/tex]

c) The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

Explanation:

The rate of accumulation of money is

dS/dt=rS

To calculate the amount of money accumulted in a period, we have to rearrange and integrate:

\int dS/S=\int rdt=r \int dt\\\\ln(S)=C*r*t\\\\S=C*e^{rt}

When t=0, S=S₀ (the initial capital).

S=S_0=Ce^{r*0}=Ce^0=C\\\\C=S_0

Now we have the equation for the capital in function of time:

S=S_0e^{rt}

a) For an initial capital of $4000 and for a period of five years, the amount of capital accumulated for this interest rates is:

- r=5%: S=4000e^{0.05*5}=4000*e^{0.25}= 5,136.10

- r=4%: S=4000e^{0.04*5}=4000*e^{0.20}=  4,885.61

- r=3%: S=4000e^{0.03*5}=4000*e^{0.15}=   4,647.34

b) We can express this as

S=S_0e^{rt}\\\\2S_0=S_0e^{rt}\\\\2=e^{rt}\\\\ln(2)=rt\\\\t=ln(2)/r

- r=5%: t=ln(2)/0.05=14

- r=4%: t=ln(2)/0.04=17

- r=3%: t=ln(2)/0.03=  23

c) When the interest is compuonded quarterly, the anual period is divided by 4. In 5 years, there are 4*5=20 periods of capitalization. The annual rate r=0.0525 to calculate the interest is also divided by 4:

S = 4000 (1+(1/4)(0.0525))^{5*4}=4000(1.013125)^{20}\\\\S=4000*1.297958= 5,191.83

If compuonded continously, we have:

S=S_0e^{rt}=4000*e^{0.0525*5}=4000*1.3= 5,200.71

The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

5 0
3 years ago
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