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olga2289 [7]
2 years ago
5

A coin is flipped three times, and the following list shows the possible outcomes.

Mathematics
1 answer:
ahrayia [7]2 years ago
5 0

Answer:

3 outcomes

Step-by-step explanation:

question asks only 1 head therefore THT, TTH, HTT

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You read 165 pages in 3 hours find the unit rate
Aliun [14]

Answer:

55 pages per hour

Step-by-step explanation:

You divide 165 by 3 = 55

8 0
3 years ago
SOLVE EQUATION BY TAKING SQUARE ROOTS.<br> -100+81a^2=0
IceJOKER [234]

Answer:

a = ±10/9

Step-by-step explanation:

-100+81a^2=0\\81a^2=100\\a^2=\frac{100}{81}\\\sqrt{a^2}=\sqrt{\frac{100}{81} }\\a=10/9\\a=-10/9

7 0
3 years ago
Read 2 more answers
A theater is divided into a red section and a blue section. The red section has 350 seats, and the rest of the seats are in the
coldgirl [10]
850.

68,750 = 350(75) + 50x
68, 750 = 26,250 + 50x
                -26250
42,500 = 50x / 50
850 = x
5 0
3 years ago
In Andrew’s Furniture Shop, he builds bookshelves and tables. Each type of furniture takes him about the same time to make. He f
olasank [31]
Given:
Cost to build a bookshelf = $20
Cost to build a table = $45
Amount available to spend = $600

Let x =  number of bookshelves built.
Let y =  number of tables built.

The total number of bookshelves and tables =  18.
Therefore
x + y = 18.
 That is,
 y = 18 - x                    (1)

The total amount available to build x bookshelves and y tables = $600. Therefore
20x + 45y = 600
That is (dividing through by 5),
4x + 9y = 120            (2)

Substitute (1) into (2).
4x + 9(18 - x) = 120
4x + 162 - 9x = 120
-5x = -42
  x = 8.4
From (1),obtain
 y = 18 - 8.4 = 9.6

Because we cannot have fractional bookshelves and tables, we shall test values of x=8, 9 and y=9,10 for profit

Note: The profit is $60 per bookshelf and $100 per table.
If x = 8, then y = 18-8 = 10.
The profit = 8*60 + 10*100 =  $1480

If x = 9, then y = 18-9 = 9.
The profit = 9*60 + 9*100 = $1440

The choice of 8 bookshelves and 10 tables is more profitable.

Answer: 8 bookshelves and 10 tables.
5 0
3 years ago
Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
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